本文實例講述了JavaScript實現構造json數組的方法。分享給大家供大家參考，具體如下：
從后端拿到的數據是一個數組，每個元素中包含的數據如下(host相同的記錄都是相鄰的)
currentTime:"1470729601"
host:"10.3.34.21"
taskList:null
taskNum:1
想構造類似如下結構的json數組
[{ name: 'host:10.1.6.49', data: [ [1470641461000, 5], [1470642581000, 4], [1470643701000, 2], [1470647341000, 3] ]}, { name: 'host:10.3.34.18', data: [ [1470641461000, 2], [1470642581000, 2], [1470643701000, 1], [1470647341000, 4] ]}, { name: 'host:10.2.2.22', data: [ [1470641461000, 3], [1470642581000, 2], [1470643701000, 6], [1470647341000, 4] ]},{ name: 'host:10.1.110.96', data: [ [1470641461000, 1], [1470642581000, 8], [1470643701000, 1], [1470647341000, 1] ]},{ name: 'host:10.2.2.87', data: [ [1470641461000, 7], [1470642581000, 3], [1470643701000, 6], [1470647341000, 5] ]}]錯誤的方式：
var backendData = data.result;var resultList = new Array();var curHost = "";var oneHostDataList = new Array();for (var i in backendData) { var host = backendData[i].host; if (host != curHost) { if(i != 0) { var item = new Object(); item.name = curHost; item.data = oneHostDataList; resultList.push(item); } oneHostDataList = new Array(); curHost = host; } else { var dot = new Array(); dot.push(backendData[i].currentTime * 1000); dot.push(backendData[i].taskNum); oneHostDataList.push(dot); }}var item = new Object();item.name = curHost;item.data = oneHostDataList;resultList.push(item);$scope.data = JSON.stringify(resultList);以上方式的問題在于轉換后會使得name和host和帶上引號，正確的方式如下：
var backendData = data.result;var resultList = [];var curHost = "";var oneHostDataList = new Array();for (var i in backendData) { var host = backendData[i].host; if (host != curHost) { if(i != 0) { var item = { name: curHost, data: oneHostDataList }; resultList.push(item); } oneHostDataList = new Array(); curHost = host; } else { var dot = new Array(); dot.push(backendData[i].currentTime * 1000); dot.push(backendData[i].taskNum); oneHostDataList.push(dot); }}var item = new Object();item.name = curHost;item.data = oneHostDataList;resultList.push(item);$scope.data = resultList;希望本文所述對大家JavaScript程序設計有所幫助。
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