基于jquery異步傳輸json數據格式實例代碼

2024-05-06 15:56:04

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這篇文章主要介紹了jquery異步傳輸json數據格式實例代碼，有需要的朋友可以參考一下

1.jsp代碼如下

復制代碼代碼如下:

<%@ page language="java" contentType="text/html; charset=UTF-8"
    pageEncoding="UTF-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
<script type="text/javascript" src="<%=basePath%>js/jquery-1.8.1.js"></script>
</head>
<script type="text/javascript">
$(function(){
  $("#getResult").click(function(){
   $.ajax({
    type:"post",
    url:"<%=basePath%>jsonAction!getData.action",
    dataType:"json",
    data:{'param1':$("#param1").attr("value"),'param2':$("#param2").attr("value")},
    success:function(returnData){
     var html = "<table><tr><td>編號</td><td>姓名</td><td>描述</td></tr>";
     for(var i = 0; i < returnData.length; i++){
      html += "<tr><td>"+returnData[i].id+"</td><td>"+returnData[i].name+"</td><td>"+returnData[i].description+"</td></tr>";
     }
     $("#result").html(html);
    }
   });
  });

});
</script>
<body>
<input type="text" value="haha">
<input type="text" value="hehe">
<div ></div>
<input type="button" value="獲取">
</body>
</html>

2.訪問 action代碼如下

復制代碼代碼如下:

public class JsonAction extends ActionSupport{
public void getData() throws IOException
{
  HttpServletRequest req = ServletActionContext.getRequest();
  String p1 = req.getParameter("param1");
  String p2 = req.getParameter("param2");

  HttpServletResponse rep = ServletActionContext.getResponse();
  rep.setContentType("text/json;charset=utf-8");
  PrintWriter pw = rep.getWriter();
  String data = "[{/"id/":/"01/",/"name/":/"zhongqian/",/"description/":/""+p1+"/"},{/"id/":/"02/",/"name/":/"zhangsan/",/"description/":/""+p2+"/"}]";
  pw.print(data);
  pw.flush();
}
}

3.效果如下：