php+ajax+json 實例代碼
html頁面:
<html><head><meta http-equiv="content-type" content="text/html;charset=utf-8" /><script type="text/javascript" src="jquery-1.8.2.min.js"></script><script type="text/javascript"> $(function(){   $("#send").click(function(){    var cont = $("input").serialize();    $.ajax({      url:'ab.php',      type:'post',      dataType:'json',      data:cont,      success:function(data){       var str = data.username + data.age + data.job;       $("#result").html(str);    }  }); });  });</script></head><body><div id="result">一會看顯示結果</div><form id="my" action="" method="post">      <p><span>姓名:</span> <input type="text" name="username" /></p>     <p><span>年齡:</span><input type="text" name="age" /></p>     <p><span>工作:</span><input type="text" name="job" /></p></form><button id="send">提交</button></body></html>php頁面:
<?phpheader("Content-type:text/html;charset=utf-8");    $username = $_POST['username'];    $age = $_POST['age'];    $job = $_POST['job'];    $json_arr = array("username"=>$username,"age"=>$age,"job"=>$job);    $json_obj = json_encode($json_arr);    echo $json_obj;?> 使用post方式
<script type="text/javascript"> $(function(){ $("#send").click(function(){   var cont = {username:$("input")[0].value,age:$("input")[1].value,job:$("input")[2].value};   var url = 'ab.php';   $.post(url,cont,function(data){    var res = eval("(" + data + ")");//轉為Object對象   var str = res.username + res.age + res.job;  $("#result").html(str);  }); });  });</script>感謝閱讀,希望能幫助到大家,謝謝大家對本站的支持!
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