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一個簡單的網頁密碼登陸php代碼

2024-05-04 23:14:39

字體：大中小

來源：轉載

供稿：網友

復制代碼代碼如下:

<?php
$password = "1234"; // 這里是密碼
$p = "";
if(isset($_COOKIE["isview"]) and $_COOKIE["isview"] == $password){
$isview = true;
}else{
if(isset($_POST["pwd"])){
if($_POST["pwd"] == $password){
setcookie("isview",$_POST["pwd"],time()+3600*3);
$isview = true;
}else{
$p = (empty($_POST["pwd"])) ? "需要密碼才能查看，請輸入密碼。" : "密碼不正確，請重新輸入。";
}
}else{
$isview = false;
$p = "請輸入密碼查看，獲取密碼可聯系我。";
}
}
if($isview){ ?>
這里是密碼成功后顯示的地方
<?php }else{ ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" " ">
<html xmlns=" ">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<meta http-equiv="pragma" content="no-cache" />
<meta http-equiv="cache-control" content="no-cache" />
<meta http-equiv="expires" content="0" />
<title>武林網提醒你輸入密碼</title>

<style type="text/css">

</style>
<div>
<div>
<form action="?yes" method="post">輸入查看密碼
<input type="password" /> <input type="submit" value="查看" />
</form>
<?php echo $p; ?>
</div>
</div>
<?php
} ?>
</body>
</html>