php登錄與退出登錄實例代碼

2024-05-04 21:57:37

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這里我們pm_user是數(shù)據(jù)表沒有創(chuàng)建表,大家可以自己行創(chuàng)建了,下面只介紹利用php登錄然后再退出登錄的程序代碼,有需要的朋友可進行參考.

實例代碼如下:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">

<head>

<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />

<title>無標題文檔</title>

</head>

<body>

<form id="form1" name="form1" method="post" action="">

  <p>

    <label for="user"></label>

    <input type="text" name="user" id="user" />

  </p>

  <p>

    <label for="pwd"></label>

    <input type="text" name="pwd" id="pwd" />

  </p>

  <p>

    <input type="submit" name="button" id="button" value="提交" />

  </p>

</form>

</body>

</html>

實例代碼如下:

function showPage() //判斷是否登錄未登錄直接跳轉至登錄頁面

{

if(!isset($_SESSION["user"]) && !isset($_SESSION["pwd"]))

{

  if(isset($_COOKIE["user"]) && isset($_COOKIE["pwd"]))

  {

   $sql = "select * from pm_user where u_user='$_COOKIE[user]'";

   $query = mysql_query($sql);

   $isUser = is_array($row = mysql_fetch_array($query)); //判斷用戶名

   $isPwd = $isUser ? $row["u_pwd"] == $_COOKIE["pwd"] : false; //判斷密碼

   if($isPwd)

   {

    $_SESSION["user"]  = $_COOKIE["user"];

    $_SESSION["pwd"]   = $_COOKIE["pwd"];

    $_SESSION["id"]    = $_COOKIE["id"];

    $_SESSION["name"]  = $_COOKIE["name"];

   }

  }

}

if(!isset($_SESSION["user"]) && !isset($_SESSION["pwd"]))

{

  echo '<script>alert("你還沒登錄！正在返回登錄頁面...");location.href="index.php";</script>';

  exit();

}

}

退出登錄

out.php

實例代碼如下:

function loginOut() //登出函數(shù)

{

if(isset($_GET["login"]) == 'out')

{

  $_SESSION["user"]  = '';

  $_SESSION["pwd"]   = '';

  $_SESSION["id"]    = '';

  $_SESSION["name"]  = '';

  session_destroy();

  echo '<script>alert("退出成功！");location.href="index.php"; </script>';

}

}