PHP中使用最多的非Array莫屬了,那Array是如何實現(xiàn)的?在PHP內(nèi)部Array通過一個hashtable來實現(xiàn),其中使用鏈接法解決hash沖突的問題,這樣最壞情況下,查找Array元素的復(fù)雜度為O(N),最好則為1.
- static inline ulong zend_inline_hash_func(const char *arKey, uint nKeyLength)
- {
- register ulong hash = 5381; //此處初始值的設(shè)置有什么玄機(jī)么?
- /* variant with the hash unrolled eight times */
- for (; nKeyLength >= 8; nKeyLength -= 8) { //這種step=8的方式是為何?
- hash = ((hash << 5) + hash) + *arKey++;
- hash = ((hash << 5) + hash) + *arKey++;
- hash = ((hash << 5) + hash) + *arKey++;
- hash = ((hash << 5) + hash) + *arKey++; //比直接*33要快
- hash = ((hash << 5) + hash) + *arKey++;
- hash = ((hash << 5) + hash) + *arKey++;
- hash = ((hash << 5) + hash) + *arKey++;
- hash = ((hash << 5) + hash) + *arKey++;
- }
- switch (nKeyLength) {
- case 7: hash = ((hash << 5) + hash) + *arKey++; /* fallthrough... */ //此處是將剩余的字符hash //開源代碼Vevb.com
- case 6: hash = ((hash << 5) + hash) + *arKey++; /* fallthrough... */
- case 5: hash = ((hash << 5) + hash) + *arKey++; /* fallthrough... */
- case 4: hash = ((hash << 5) + hash) + *arKey++; /* fallthrough... */
- case 3: hash = ((hash << 5) + hash) + *arKey++; /* fallthrough... */
- case 2: hash = ((hash << 5) + hash) + *arKey++; /* fallthrough... */
- case 1: hash = ((hash << 5) + hash) + *arKey++; break;
- case 0: break;
- EMPTY_SWITCH_DEFAULT_CASE()
- }
- return hash;//返回hash值
- }
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