names=["zhao00","qian01","sun02","li03","li03","li03","zhou04"]#print(names[]) 打印錯誤print(names)

names.append("wu05") #增加到最后names.insert(1,"zheng06") #增加到指定位置

names[0]="zhao" #改

#names.remove("zheng06")#del names[5]#names.pop() #  沒有下標，默認刪掉最后一個#names.pop(0)#print(names)#del names 把整個列表刪除#names.clear() 把列表的元素刪除

print(names.index("qian01")) #查位置print(names[names.index("qian01")])#并打印數據print(names.count("li03"))#統計相同元素的個數

names2=["01","02","03"]names.extend(names2) #合并

print(names[0:3]) #左閉右開，等效于[:3]print(names[-1]) #取最后一個print(names[-2:]) #取最后兩個，[-2:0],[-2:-1]不行

.print(names)----------.for i in names: print(i)----------.print(names[0:-1:1]) #間隔一個輸出print(names[0:-1:2])