掃描整個網段的多線程程序

2019-11-17 06:00:11

字體：大中小

來源：轉載

供稿：網友

　　掃描500個ip10秒鐘左右, 一個IP等待0.3秒

用java寫的過程編程,供參考:

package steeven;

import java.sql.*;

import java.io.*;

import java.util.*;

import java.text.*;

import javax.servlet.http.*;

public class Ip extends Common implements Runnable{

public String ip; // IP, 用戶名, 主機名

ResultSet list; // 分頁顯示的記錄集

public Ip cur; // 分頁顯示的當前記錄

static public Hashtable ping = new Hashtable(); //ping 后的結果集

static int threadCount = 0; //當前線程的數量, 防止過多線程摧毀電腦

public Ip() {}

public Ip(String ip){

this.ip=ip;

Thread r = new Thread(this);

r.start();

}

public static void Ping(String ip) throws Exception{

//最多30個線程

while(threadCount>30)

Thread.sleep(50);

threadCount +=1;

Ip p = new Ip(ip);

}

public void PingAll() throws Exception{

threadCount =0;

ping = new Hashtable();

while(next()) //next()對所有局域網Ip放到cur

Ping(cur.ip);

//等著所有Ping結束

while(threadCount>0)

Thread.sleep(50);

}

public void run(){

try{

PRocess p= Runtime.getRuntime().exec ("ping "+ip+ " -w 300 -n 1");

InputStreamReader ir = new InputStreamReader(p.getInputStream());

LineNumberReader input = new LineNumberReader (ir);

//讀取結果行

for (int i=1 ; i<7; i++)

input.readLine();

String line= input.readLine();

if (line.length()<17 line.substring(8,17).equals("timed out"))

ping.put(ip,new Boolean(false));

else

ping.put(ip,new Boolean(true));

//線程結束

threadCount -= 1;

}catch (IOException e){}

}

public static void main(String[] args) throws Exception{

Ip ip= new Ip();

ip.PingAll();

java.util.Enumeration key = ping.keys();

String k;

while((k = (String)key.nextElement()) != null)

System.out.println(k+": "+ping.get(k));

}

}

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