a=0for i in range(1,1000):    if i%3==0 or i%5==0:        a += iprint "1000以內(nèi)3和5的倍數(shù)之和:",a

sum1=0sum2=0i=1j=1while j<4000000:      j=i+j      i=j-i      if i%2==0:        sum1=i+sum1    print"小于4000000的斐波那契數(shù)列和：" ,sum1

count=1for i in range(100,999):  for n in range(100,999):      c=n*i      e1=c%10      c=c/10      e2=c%10      c=c/10      e3=c%10      c=c/10      e4=c%10      c=c/10      e5=c%10      c=c/10      e6=c%10      c=c/10      if e1==e6 and e2==e5 and e3==e4:        if count < n*i:          count = n*i          print count

a=3f=1for i in range(10**(a-1),10**a-1):   for n in range(10**(a-1),10**a-1):       c=n*i       d=str(c)       e=d[::-1]       if d==e:          if f<n*i:             f=n*iprint f

count=1num=3def findPrime(s):#判斷一個數(shù)是否為質(zhì)數(shù)    i=2
    import math    while i<math.sqrt(s)+1:#依據(jù)質(zhì)數(shù)判定法則
        if s%i == 0:            return False        else:            i=i+1    return Truewhile count <10001:#尋找第10001個質(zhì)數(shù)    if findPrime(num):        count =count + 1        num = num +2    else:        num = num+2print num-2

def findabc(h):    for a in range(1,h):        for d in range(1,h):            b=d            c=1000-a-d            if (a**2+b**2==c**2) and (c>=0) and (a<b<c):
                print a,b,c #該程序會輸出a,b,c的值                print a*b*cfindabc(1000)


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i=2count =0while i<2000000:    if findPrime(i):#第7題中的一個函數(shù)        count +=i        i +=1    else:        i +=1print count