題目描述:Implement wildcard pattern matching with support for '?' and '*'.'?' Matches any single character.'*' Matches any sequence of characters (including the empty sequence).The matching should cover the entire input string (not partial).The function PRototype should be:bool isMatch(const char *s, const char *p)Some examples:isMatch("aa","a") → falseisMatch("aa","aa") → trueisMatch("aaa","aa") → falseisMatch("aa", "*") → trueisMatch("aa", "a*") → trueisMatch("ab", "?*") → trueisMatch("aab", "c*a*b") → false實現字符串匹配。輸入字符串s,和字符串匹配p,?可被替換為任何非空字符,*可替換空字符或任何字符。設,arr[i,j]表示s的第i個字符是否和p的第j個字符匹配。對于s[i]和p[j],分為三種情況:arr[i,j] = arr[i-1,j-1] ,p[j]=?arr[i,j] = arr[i-1,j-1] && s[i-1] == p[j-1] ,p[j]為普通字符arr[i,j] = arr[i-1,j-1]||arr[i-1,j]||arr[i,j-1] ,p[j]為*實現代碼:public class Solution { public bool IsMatch(string s, string p) { var dp = new bool[s.Length + 1, p.Length + 1]; dp[0,0] = true; // s is empty , pattern is empty, match // s is not empty , patter is empty , not match for (var i = 0;i < s.Length; i++){ dp[i+1,0] = false; } // pattern not empty, s is empty , not match for (var i = 0;i < p.Length; i++){ dp[0, i+1] = p[i] == '*' && dp[0, i]; } for (var i = 1; i <= s.Length; i++){ for (var j = 1;j <= p.Length; j++){ if (p[j-1] == '?'){ dp[i,j] = dp[i-1,j-1]; // depends on previous match or no } else if(p[j-1] == '*'){ // 1. ab a* // 2. bavfdc b* // pattern j matches string i - 1 (* is any char) // or // pattern j-1 matches string i (* can be removed) //Console.WriteLine(i+","+j); dp[i,j] = dp[i-1,j] || dp[i, j-1] || dp[i-1,j-1]; } else{ // pattern is a normal charactor , previous match also current char should match dp[i,j] = dp[i-1,j-1] && s[i-1] == p[j-1]; } } } //Console.WriteLine(dp); return dp[s.Length,p.Length]; }}