以下有兩個表，他們的結構完全相同，請通過SQL找出值不同的列。 Student_1 NAME AGE SCORE peter 26 100 jack 25 96 daniel 26 48 bark 21 69 Student_2 NAME AGE SCORE peter 26 89 jack 25 96 daniel 26 48 bark 21 69 方法一 -- NOT EXISTS： 復制代碼 代碼如下: SELECT * FROM Student_1 S1 WHERE NOT EXISTS (SELECT * FROM Student_2 S2 WHERE S1.name = S2.name AND S1.age = S2.age AND S1.score = S2.score ) UNION ALL SELECT * FROM STUDENT_2 S2 WHERE NOT EXISTS (SELECT * FROM STUDENT_1 S1 WHERE S1.name = S2.name AND S1.age = S2.age AND S1.score = S2.score ); 方法二 -- MINUS 復制代碼 代碼如下: (SELECT * FROM Student_1 MINUS SELECT * FROM Student_2) UNION ALL (SELECT * FROM Student_2 MINUS SELECT * FROM Student_1) 方法三 -- HAVING GROUP BY 復制代碼 代碼如下: SELECT DISTINCT name, age, score FROM ( SELECT * FROM Student_1 UNION ALL SELECT * FROM Student_2 )GROUP BY name, age, score HAVING COUNT(*)=1 ;
