本文實例講述了微信小程序實現獲取用戶信息并存入數據庫操作。分享給大家供大家參考，具體如下：

微信小程序獲取用戶信息簡單，但是在存入自己服務器數據庫的過程中研究了一天多的時間，并且網上搜索不到該資源，故發出來供大家參考。

index.js

Page({ data: {  nickName: "微信賬號登錄",  avatarUrl:"./user-unlogin.png", }, onLoad: function () {  var that = this;  var nickName = that.data.nickName ;  var avatarUrl = that.data.avatarUrl;  var db="no";  wx.getUserInfo({   success: function (res) {    that.data.nickName = res.userInfo.nickName,    that.data.avatarUrl = res.userInfo.avatarUrl,    that.setData({     nickName: that.data.nickName,     avatarUrl: that.data.avatarUrl,    }),    that.setData({     db:"ok"http:// 設置變量db，只有成功獲取用戶信息后才寫入數據庫    })    if(db = "ok") {     var name, url;     wx.request({      url: 'https://.../getuserinfo.php',//寫自己的服務器      header: {       "Content-Type": "application/x-www-form-urlencoded"      },      method: "POST",      data: {       name: res.userInfo.nickName,       url: res.userInfo.avatarUrl,      },      success: function () {       console.log("success")      },      fail: function () {       console.log("fail")      }     })    }   },   fail: function (res) {    that.data.nickName = "未授權無法獲取用戶信息",     that.setData({      nickName: that.data.nickName     })   }  }) },onShow: function () { }})

getuserinfo.php

<?php$name = $_POST['name'];$url = $_POST['url'];$servername = "localhost";$username = "root";$password = "";//服務器中連接數據庫的密碼$dbname = "mydb";//使用的數據庫名// 創建連接$conn = new mysqli($servername, $username, $password, $dbname);// 檢測連接if ($conn->connect_error) { die("connect server fail: " . $conn->connect_error);}$sql = "INSERT INTO userinfoVALUES ('$name', '$url')";if ($conn->query($sql) === TRUE) { echo "insert success";} else { echo "Error: " . $sql . "<br>" . $conn->error;}$conn->close();?>

測試通過，在服務器中查詢有用戶信息

希望本文所述對大家微信小程序開發有所幫助。