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在ASP.NET中處理 datetime 的一些通用函數(shù)(vb)

2024-07-10 12:58:00
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  • 'uses the timespan method to subtract a certain number of days
    function date1()
         dim newtime as datetime
         newtime = datetime.now.subtract( new timespan(7, 0, 0, 0) )
         newtime = newtime.format("mm/dd/yyyy", datetimeformatinfo)
         response.write(newtime)
    end function

    'uses the adddays method to subtract x number of days
    public function date2()
      dim newtime as datetime
      newtime = datetime.now.adddays(-7)
      dim s as string = newtime
      return s
    end function

    'thanks to paul czywczynski for this idea
    'this probably (in my opinion) offers the most flexibility found so far
    'change where the mm/dd/yyyy to whatever
    'response.write(system.string.format("{0:d}",newtime))
    'would return just the name of the day
    function date3()
      dim newtime as datetime = now.adddays(-7)
      response.write(system.string.format("{0:mm/dd/yyyy}",newtime))
    end function


    function date4()
    dim newtime as datetime
      newtime = now.adddays(-7)
      return newtime.tostring()
    end function

    'uses the tolongtimestring method
    public function date5()
      dim newtime as datetime
      newtime = now()
      return newtime.tolongtimestring()
    end function

    'uses the toshorttimestring method
    public function date6()
      dim newtime as datetime
      newtime = now()
      return newtime.toshorttimestring()
    end function

    'uses the tolongdatestring method
    public function date7()
      dim newtime as datetime
      newtime = now()
      return newtime.tolongdatestring()
    end function

    'uses the toshortdatestring method
    public function date8()
      dim newtime as datetime
      newtime = now()
      return newtime.toshortdatestring()
    end function

    'uses formatdatetime function general format
    function date9()
      dim newtime as datetime
      newtime = datetime.now.subtract( new timespan(7, 0, 0, 0) )
      return formatdatetime(newtime, 0)
    end function

    'uses formatdatetime function longdate format
    function date10()
      dim newtime as datetime
      newtime = datetime.now.subtract( new timespan(7, 0, 0, 0) )
      return formatdatetime(newtime, 1)
    end function

    'uses formatdatetime function shortdate format
    function date11()
      dim newtime as datetime
      newtime = datetime.now.subtract( new timespan(7, 0, 0, 0) )
      return formatdatetime(newtime, 2)
    end function

    'uses formatdatetime function longtime format
    function date12()
      dim newtime as datetime
      newtime = datetime.now.subtract( new timespan(7, 0, 0, 0) )
      return formatdatetime(newtime, 3)
    end function

    'uses formatdatetime function shorttime format
    function date13()
      dim newtime as datetime
      newtime = datetime.now.subtract( new timespan(7, 0, 0, 0) )
      return formatdatetime(newtime, 4)
    end function

    'bring back just the name of the day
    function date14()
      dim newtime as datetime = now.adddays(-7)
      dim s as string
      s = (system.string.format("{0:dddd}",newtime))
      return s
    end function

    'returns the integer of what day of week
    function date15()
      dim mydate as datetime
      dim myweekday as integer
      mydate = now.adddays(-5)
      myweekday = weekday(mydate)   
      return myweekday
    end function

    'returns the month integer
    function date16()
      dim mydate as datetime
      dim mymonth as integer
      mydate = now.adddays(-5)
      mymonth = month(mydate)   
      return mymonth
    end function

    'returns just a formatted string
    'this method provides just formatting but
    'very flexible with not a lot of code
    function date17()
      dim mydate as string
      mydate = format(now(), "yyyy")
      return mydate
    end function
    </script>
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