求字符串中最大的遞增子序列
數(shù)據(jù)庫(kù)環(huán)境:SQL SERVER 2005
如題,求字符串“abcbklmnodfghijkmer”中最大的遞增子序列。這個(gè)字符串有點(diǎn)特別,
只由26個(gè)小寫字母a-z組成。
大概思路如下:
1.將字符串轉(zhuǎn)到一列存儲(chǔ),并生成行號(hào)
2.設(shè)置一個(gè)遞增計(jì)數(shù)器列,默認(rèn)為1,比較上下行的字符,如果在字典中的順序是遞增,
則計(jì)數(shù)器加1,否則,計(jì)數(shù)器置1
3.找出計(jì)數(shù)器最大的數(shù)及對(duì)應(yīng)的行號(hào),根據(jù)這2個(gè)數(shù)截取字符串
思路有了,下面直接貼代碼
DECLARE @vtext VARCHAR(255)SET @vtext = 'abcbklmnodfghijkmer'/*講字符串轉(zhuǎn)成一列存儲(chǔ),并生成行號(hào)*/WITH x0 AS ( SELECT number AS id , SUBSTRING(@vtext, number, 1) AS letter FROM master.dbo.spt_values WHERE type = 'P' AND number <= LEN(@vtext) AND number >= 1 ),/*實(shí)現(xiàn)計(jì)數(shù)器*/ x1 ( id, letter, clen ) AS ( SELECT id , letter , 1 AS clen FROM x0 WHERE id = 1 UNION ALL SELECT x0.id , x0.letter , CASE WHEN x1.letter <= x0.letter THEN x1.clen + 1 ELSE 1 END AS clen FROM x0 , x1 WHERE x0.id = x1.id + 1 ) /*截取字符串*/ SELECT SUBSTRING(@vtext, start, sublen) AS 最大子序列 FROM ( SELECT id , clen , MAX(clen) OVER ( ) AS maxclen , id - MAX(clen) OVER ( ) + 1 AS start , MAX(clen) OVER ( ) AS sublen FROM x1 ) t WHERE clen = maxclen
求出的最大子序列是

通過(guò)以上的思路和代碼,希望可以對(duì)大家有所啟迪和幫助。
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