#!/bin/bash filename=$1echo "`whoami`"if [ $# -lt 1 ];then echo "usage : ./scripts filename" exit -1fiif [ ! -f $filename ];then echo "$filename is not a file" exit 0;fi user="`whoami`"if [ "$user" != "root" ];then echo "use scripts with root" exit 0;fi#刪除空行,空行包括：tables + spacesed '/^[[:blank:]]*$/d' $filename > "${filename}_backup"#刪除 // 所在的行sed -i '/^[[:blank:]]*/////d' "${filename}_backup"#/*xxxxx*/#打印/*所有的開始行grep -n '[[:blank:]]*/[*]' "${filename}_backup" | awk 'BEGIN{FS=":"}{print $1}' > "start.txt"#打印*/所有的結束行grep -n '[*]/[[:blank:]]*' "${filename}_backup" | awk 'BEGIN{FS=":"}{print $1}' > "end.txt"#合并兩個文件，final.txt里面每行就是/*xx..../n....xx*/這種類型注釋的開始行和起始行號paste "start.txt" "end.txt" > "final.txt"while read linedo #得到起始行 START=`echo "$line" | awk 'BEGIN{FS="/t"}{print $1}'` #得到結束行 END=`echo "$line" | awk 'BEGIN{FS="/t"}{print $2}'` #這里有一個bug，如是/*xxxx*/中的/*和*/在同一行出現,并且有代碼也在同一行 # printf("hello world/n"); /*打印字符串*/  # /*打印字符串*/ #上面兩種情況的就沒法判斷，希望大家優化 if [ $START -eq $END ];then continue fi #刪除/*到*/中間所有行 sed -i "${START},${END}d" "${filename}_backup"done < "final.txt"wc -l "${filename}_backup"rm -f "final.txt" "start.txt" "end.txt"