SQL根據(jù)指定分隔符分解字符串實(shí)現(xiàn)步驟

2020-07-25 13:12:23

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供稿：網(wǎng)友

如果有一個(gè)字符串 eg: "sun,star,moon,clouds",想要在MS SQL中根據(jù)給定的分隔符','把這個(gè)字符串分解成各個(gè)元素[sun] [star] [moon] [clouds]，如何實(shí)現(xiàn)呢？為此，創(chuàng)建一個(gè)Function,代碼如下:

復(fù)制代碼代碼如下:

 
CREATE FUNCTION [dbo].[Split_StrByDelimiter](@String VARCHAR(8000), @Delimiter CHAR(1)) 
RETURNS @temptable TABLE (items VARCHAR(8000)) 
AS 
BEGIN 
DECLARE @idx INT 
DECLARE @slice VARCHAR(8000) 
SELECT @idx = 1 
IF len(@String)<1 OR @String IS NULL RETURN 
while @idx!= 0 
BEGIN 
SET @idx = charindex(@Delimiter,@String) 
IF @idx!=0 
SET @slice = LEFT(@String,@idx - 1) 
ELSE 
SET @slice = @String 
IF(len(@slice)>0) 
INSERT INTO @temptable(Items) VALUES(@slice) 
SET @String = RIGHT(@String,len(@String) - @idx) 
IF len(@String) = 0 break 
END 
RETURN 
END 

示例：如果輸入
SELECT * FROM dbo.Split_StrByDelimiter('sun,star,moon,clouds',',')
結(jié)果返回
sun
star
moon
clouds
在上面的代碼做變形，返回有多少個(gè)元素

復(fù)制代碼代碼如下:

 
CREATE FUNCTION [dbo].[GetCount_Split_StrByDelimiter](@String VARCHAR(8000), @Delimiter CHAR(1)) 
RETURNS INT 
AS 
BEGIN 
DECLARE @temptable TABLE (items VARCHAR(8000)) 
DECLARE @SplitCount INT 
DECLARE @idx INT 
DECLARE @slice VARCHAR(8000) 
SELECT @idx = 1 
IF len(@String)<1 OR @String IS NULL RETURN 0 
while @idx!= 0 
BEGIN 
SET @idx = charindex(@Delimiter,@String) 
IF @idx!=0 
SET @slice = LEFT(@String,@idx - 1) 
ELSE 
SET @slice = @String 
IF(len(@slice)>0) 
INSERT INTO @temptable(Items) VALUES(@slice) 
SET @String = RIGHT(@String,len(@String) - @idx) 
IF len(@String) = 0 break 
END 
SET @SplitCount=(SELECT COUNT(*) FROM @temptable) 
RETURN @SplitCount 
END 