在SQL Server數據庫中如何查看一個登錄名(login)的具體權限呢,如果使用SSMS的UI界面查看登錄名的具體權限的話,用戶數據庫非常多的話,要梳理完它所有的權限,操作又耗時又麻煩,個人十分崇尚簡潔、高效的方法,反感那些需要大量手工操作的UI界面操作方式,哪怕就是腳本,如果不能一次搞定,手工多操作幾次(例如,切換數據庫),都是不可接受的。最近遇到這個需求,就完善了一下之前的腳本get_login_rights_script.sql,輸入登錄名參數,將這個登錄名所擁有的服務器角色、數據庫角色、以及所授予具體對象的相關權限使用腳本查詢出來,腳本分享如下:
--==================================================================================================================-- ScriptName : get_login_rights_script.sql-- Author : 瀟湘隱者 -- CreateDate : 2015-12-18-- Description : 查看某個登錄名被授予的數據庫對象的權限的腳本(授權腳本和回收權限腳本)-- Note : /****************************************************************************************************************** Parameters : 參數說明******************************************************************************************************************** @login_name : 你要查看權限的登錄名(需要輸入替換的參數)******************************************************************************************************************** Modified Date Modified User Version Modified Reason******************************************************************************************************************** 2018-08-03 瀟湘隱者 V01.00.00 新建該腳本。 2019-04-04 瀟湘隱者 V01.01.00 Fix掉一個bug,某個表只允許更新某個字段,但是這里顯示更新整個表。 2019-09-25 瀟湘隱者 V01.02.00 解決只能查看某個用戶數據庫,不能查看所有數據庫的權限問題。 2019-09-25 瀟湘隱者 V01.03.00 解決數據庫名包含中劃線[-], 出現下面錯誤問題-------------------------------------------------------------------------------------------------------------------Msg 911, Level 16, State 1, Line 1Database 'xxxx' does not exist. Make sure that the name is entered correctly.-------------------------------------------------------------------------------------------------------------------*******************************************************************************************************************/DECLARE @login_name NVARCHAR(32)= 'test1';DECLARE @database_name NVARCHAR(64);DECLARE @cmdText NVARCHAR(MAX);IF OBJECT_ID('TempDB.dbo.#databases') IS NOT NULL DROP TABLE dbo.#databases;CREATE TABLE #databases( database_id INT, database_name sysname);IF OBJECT_ID('tempdb.dbo.#user_db_roles') IS NOT NULL DROP TABLE dbo.#user_db_roles;CREATE TABLE dbo.#user_db_roles( [DB_NAME] NVARCHAR(64) ,[USER_NAME] NVARCHAR(64) ,[ROLE_NAME] NVARCHAR(64));IF OBJECT_ID('tempdb.dbo.#user_object_rights') IS NOT NULL DROP TABLE dbo.#user_object_rights;CREATE TABLE dbo.#user_object_rights( [DATABASE_NAME] NVARCHAR(128), [SCHEMA_NAME] NVARCHAR(64), [OBJECT_NAME] NVARCHAR(128), [USER_NAME] NVARCHAR(32), [PERMISSIONS_TYPE] CHAR(12), [PERMISSION_NAME] NVARCHAR(128), [PERMISSION_STATE] NVARCHAR(64), [CLASS_DESC] NVARCHAR(64), [COLUMN_NAME] NVARCHAR(32), [STATE_DESC] NVARCHAR(64), [GRANT_STMT] NVARCHAR(MAX), [REVOKE_STMT] NVARCHAR(MAX))INSERT INTO #databasesSELECT database_id , nameFROM sys.databasesWHERE name NOT IN ('model') AND state = 0; --state_desc=ONLINE --登錄名授予的服務器角色SELECT UserName = u.name , ServerRole = g.name , Type = u.type, Type_Desc = u.Type_Desc, Create_Date = u.create_date, Modify_Date = u.modify_date, DenyLogin = l.denyloginFROM sys.server_role_members m INNER JOIN sys.server_principals g ON g.principal_id = m.role_principal_id INNER JOIN sys.server_principals u ON u.principal_id = m.member_principal_id INNER JOIN sys.syslogins l ON u.name = l.nameWHERE l.name=@login_nameORDER BY u.name,g.name;WHILE 1= 1BEGIN SELECT TOP 1 @database_name= database_name FROM #databases ORDER BY database_id; IF @@ROWCOUNT =0 BREAK; SET @cmdText = N'USE ' + QUOTENAME(@database_name) + N';' +CHAR(10) --登錄名授予的數據庫角色 SELECT @cmdText += N'INSERT INTO #user_db_roles SELECT DB_NAME() AS [DB_NAME] ,M.NAME AS [USER_NAME] ,R.NAME AS [ROLE_NAME] FROM sys.DATABASE_ROLE_MEMBERS RM INNER JOIN sys.DATABASE_PRINCIPALS R ON RM.ROLE_PRINCIPAL_ID = R.PRINCIPAL_ID INNER JOIN sys.DATABASE_PRINCIPALS M ON RM.MEMBER_PRINCIPAL_ID = M.PRINCIPAL_ID WHERE M.NAME=@p_login_name' + CHAR(10); EXEC SP_EXECUTESQL @cmdText, N'@p_login_name NVARCHAR(32)',@p_login_name=@login_name; SET @cmdText = N'USE ' +QUOTENAME(@database_name) + N';' +CHAR(10); --查看具體對象的授權問題 SELECT @cmdText +=N'INSERT INTO dbo.#user_object_rights ( [DATABASE_NAME] , [SCHEMA_NAME] , [OBJECT_NAME] , [USER_NAME] , [PERMISSIONS_TYPE] , [PERMISSION_NAME] , [PERMISSION_STATE] , [CLASS_DESC] , [COLUMN_NAME] , [STATE_DESC] , [GRANT_STMT] , [REVOKE_STMT] ) SELECT DB_NAME() AS [DATABASE_NAME] , SYS.SCHEMAS.NAME AS [SCHEMA_NAME] , ob.NAME AS [OBJECT_NAME] , SYS.DATABASE_PRINCIPALS.NAME AS [USER_NAME] , dp.TYPE AS [PERMISSIONS_TYPE] , dp.PERMISSION_NAME AS [PERMISSION_NAME] , dp.STATE AS [PERMISSION_STATE] , dp.CLASS_DESC AS [CLASS_DESC] , sc.name AS [COLUMN_NAME] , dp.STATE_DESC AS [STATE_DESC] , dp.STATE_DESC + '' '' + dp.PERMISSION_NAME + '' ON [''+ SYS.SCHEMAS.NAME + ''].['' + ob.NAME + ''] TO ['' + SYS.DATABASE_PRINCIPALS.NAME + ''];'' COLLATE LATIN1_GENERAL_CI_AS AS [GRANT_STMT] , ''REVOKE '' + dp.PERMISSION_NAME + '' ON [''+ SYS.SCHEMAS.NAME + ''].['' + ob.NAME + ''] FROM ['' + SYS.DATABASE_PRINCIPALS.NAME + ''];'' COLLATE LATIN1_GENERAL_CI_AS AS [REVOKE_STMT] FROM SYS.DATABASE_PERMISSIONS dp LEFT OUTER JOIN SYS.OBJECTS ob ON dp.MAJOR_ID = ob.OBJECT_ID LEFT OUTER JOIN SYS.SCHEMAS ON ob.SCHEMA_ID = SYS.SCHEMAS.SCHEMA_ID LEFT OUTER JOIN SYS.DATABASE_PRINCIPALS ON dp.GRANTEE_PRINCIPAL_ID = SYS.DATABASE_PRINCIPALS.PRINCIPAL_ID LEFT OUTER JOIN SYS.columns sc ON ob.object_id = sc.object_id AND sc.column_id = dp.minor_id WHERE SYS.DATABASE_PRINCIPALS.NAME =@p_login_name ORDER BY PERMISSIONS_TYPE;' PRINT(@cmdText); EXEC SP_EXECUTESQL @cmdText, N'@p_login_name NVARCHAR(32)',@p_login_name=@login_name; DELETE FROM #databases WHERE database_name=@database_name;ENDSELECT * FROM tempdb.dbo.#user_db_roles;SELECT * FROM dbo.#user_object_rights;IF OBJECT_ID('TempDB.dbo.#databases') IS NOT NULL DROP TABLE dbo.#databases;IF OBJECT_ID('tempdb.dbo.#user_db_roles') IS NOT NULL DROP TABLE dbo.#user_db_roles;IF OBJECT_ID('tempdb.dbo.#user_object_rights') IS NOT NULL DROP TABLE dbo.#user_object_rights;總結
以上所述是小編給大家介紹的SQL Server查看login所授予的具體權限問題,希望對大家有所幫助,如果大家有任何疑問請給我留言,小編會及時回復大家的。在此也非常感謝大家對武林網網站的支持!
如果你覺得本文對你有幫助,歡迎轉載,煩請注明出處,謝謝!
新聞熱點
疑難解答