int GetAbsDays(MyDate x)
{
 int i;
 int month_day[] = {31,28,31,30,31,30,31,31,30,31,30,31};
 int year = x.year-1;  // 因?yàn)橛缶嚯x1年1月1日的距離
 int days = year * 365 + year/4 - year/100 + year/400;  //求得之前閏年的數(shù)量并在天數(shù)上進(jìn)行想加
 if(x.year%4==0 && x.year%100!=0 || x.year%400==0) month_day[1]++; //當(dāng)前年為閏年，二月加 1
 for(i=0; i<x.month-1; i++)
  days += month_day[i];
 days += x.day-1;  //今天應(yīng)該是不算如天數(shù)計(jì)數(shù)
 return days;
}

int GetDiffDays(MyDate a, MyDate b)
{
 return GetAbsDays(b) - GetAbsDays(a);
}

int main(int argc, char* argv[])
{
 MyDate a = {1842,5,18};
 MyDate b = {2000,3,13};
 int n = GetDiffDays(a,b);
 printf("%d/n", n);
}