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C/C++仿華容道小游戲

2020-01-26 14:43:42
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本文實例介紹了C++模仿華容道小游戲?qū)崿F(xiàn)代碼,分享給大家供大家參考,具體內(nèi)容如下

#include <stdio.h>#include <stdlib.h>#include <time.h>#include <stdbool.h> #define maxnum 16#define colnum 4 bool numexists(int *numbers, int length, int num);int getnumber(int **numbers, int randIndex, int *length);int* initnumbers(void);void swap(int **a, int **b); int main(int argc, char *argv[]){  int *tempnumbers = initnumbers();  int *randnumbers = initnumbers();  int **numbers;  numbers = malloc(maxnum * sizeof(int*));  //bool a = numexists(numbers, 16, 3);  //printf("a=%d/n", a);   int length = maxnum;  srand((unsigned)time(NULL));  for (int i = 0; i < maxnum; i++)  {    int temp = getnumber(&tempnumbers, rand() % length, &length);    randnumbers[i] = temp;    numbers[temp] = &randnumbers[i];    //printf("%d%c", temp, (i + 1) % colnum == 0?'/n':'/t');  }  if (tempnumbers != NULL)    free(tempnumbers);  while (true)  {    system("clear");    for (int i = 0; i < maxnum; i++)      printf("%d%c", randnumbers[i], (i + 1) % colnum == 0?'/n':'/t');     printf("move number/ invalid num==exit: ");    int i;    if (!scanf("%d", &i))    {      printf("game over/n");      break;    }    if (i >= maxnum || i <0)    {      printf("sorry, i can't find %d/n", i);      break;    }    unsigned char sign = abs(numbers[i] - numbers[0]);    switch (sign)    {      case 1:      case 4: swap(&numbers[0], &numbers[i]); break;     }   }  if (numbers != NULL)    free(numbers);  if (randnumbers != NULL)    free(randnumbers);} void swap(int **a, int **b){  int *templocation = *a;  int tempvalue = **a;  **a = **b;  **b = tempvalue;  *a = *b;  *b = templocation;} int* initnumbers(void){  int *numbers = malloc(maxnum * sizeof(int));  for (int i = 0; i < maxnum; i++)    numbers[i] = i;  return numbers;} int getnumber(int **numbers, int randIndex, int *length){  int result = (*numbers)[randIndex];  (*numbers)[randIndex] = (*numbers)[--(*length)];  int *temp = realloc(*numbers, (*length) * sizeof(int));  *numbers = temp;  return result;} bool _numexists(int *numbers, int start, int end, int num){  printf("start: %d, end: %d, num: %d/n", start, end, num);  if (start == end)    return numbers[start] == num;  else  {    int middle = (start+end) / 2;    if (numbers[middle] == num)      return true;    else if (numbers[middle] > num)      return _numexists(numbers, start, middle-1, num);    else      return _numexists(numbers, middle+1, end, num);  }}bool numexists(int *numbers, int length, int num){  return _numexists(numbers, 0, length-1, num);  }

希望本文對大家學(xué)習C++程序設(shè)計有所幫助。

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