本文實例講述了C語言使用深度優先搜索算法解決迷宮問題。分享給大家供大家參考,具體如下:
深度優先搜索

偽代碼
(Pseudocode)如下:
將起點標記為已走過并壓棧;while (棧非空) {從棧頂彈出一個點p;if (p這個點是終點)break;否則沿右、下、左、上四個方向探索相鄰的點if (和p相鄰的點有路可走,并且還沒走過)將相鄰的點標記為已走過并壓棧,它的前趨就是p點;}if (p點是終點) {打印p點的坐標;while (p點有前趨) {p點 = p點的前趨;打印p點的坐標;}} else沒有路線可以到達終點;C語言代碼:
#include <stdio.h>#define MAX_ROW 5#define MAX_COL 5struct point { int row, col; } stack[512];int top = 0;void push(struct point p){  stack[top++] = p;}struct point pop(void){  return stack[--top];}int is_empty(void){  return top == 0;}int maze[MAX_ROW][MAX_COL] = {  0, 1, 0, 0, 0,  0, 1, 0, 1, 0,  0, 0, 0, 0, 0,  0, 1, 1, 1, 0,  0, 0, 0, 1, 0,};void print_maze(void){  int i, j;  for (i = 0; i < MAX_ROW; i++) {  for (j = 0; j < MAX_COL; j++)  printf("%d ", maze[i][j]);  putchar('/n');  }  printf("*********/n");}struct point predecessor[MAX_ROW][MAX_COL] = {  {{-1,-1}, {-1,-1}, {-1,-1}, {-1,-1}, {-1,-1}},  {{-1,-1}, {-1,-1}, {-1,-1}, {-1,-1}, {-1,-1}},  {{-1,-1}, {-1,-1}, {-1,-1}, {-1,-1}, {-1,-1}},  {{-1,-1}, {-1,-1}, {-1,-1}, {-1,-1}, {-1,-1}},  {{-1,-1}, {-1,-1}, {-1,-1}, {-1,-1}, {-1,-1}},};void visit(int row, int col, struct point pre){  struct point visit_point = { row, col };  maze[row][col] = 2;  predecessor[row][col] = pre;  push(visit_point);}int main(void){  struct point p = { 0, 0 };  maze[p.row][p.col] = 2;  push(p);  while (!is_empty()) {    p = pop();    if (p.row == MAX_ROW - 1 /* goal */     && p.col == MAX_COL - 1)    break;    if (p.col+1 < MAX_COL /* right */  && maze[p.row][p.col+1] == 0)      visit(p.row, p.col+1, p);    if (p.row+1 < MAX_ROW /* down */ && maze[p.row+1][p.col] == 0)      visit(p.row+1, p.col, p);    if (p.col-1 >= 0 /* left */ && maze[p.row][p.col-1] == 0)      visit(p.row, p.col-1, p);    if (p.row-1 >= 0 /* up */  && maze[p.row-1][p.col] == 0)      visit(p.row-1, p.col, p);    print_maze();  }  if (p.row == MAX_ROW - 1 && p.col == MAX_COL - 1)  {    printf("(%d, %d)/n", p.row, p.col);    while (predecessor[p.row][p.col].row != -1) {      p = predecessor[p.row][p.col];      printf("(%d, %d)/n", p.row,      p.col);    }  } else    printf("No path!/n");    return 0;}希望本文所述對大家C語言程序設計有所幫助。
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