#include<iostream>#include<string>#include<algorithm>using namespace std;#define n 10string dezero(string a)//用來去掉正數(shù)前面的0，也就是說可以輸入000001類似這樣的數(shù)字{ long int i; for(i=0;i<a.length();i++) { if(a.at(i)>48) break; } if(i==a.length()) return "0"; a.erase(0,i); return a;}string add(string a,string b)//自然數(shù)加法{ a=dezero(a); b=dezero(b); string c; string d="0"; long int kmin,kmax,i; reverse(a.begin(),a.end()); reverse(b.begin(),b.end()); if(a.length()>b.length()) {kmin=b.length();kmax=a.length();c=a;} else {kmin=a.length();kmax=b.length();c=b;} c.insert(c.length(),d); for(i=0;i<kmin;i++) { if(a.at(i)>=48&&a.at(i)<=57) a.at(i)-=48; if(a.at(i)>=97&&a.at(i)<=122) a.at(i)-=87; if(b.at(i)>=48&&b.at(i)<=57) b.at(i)-=48; if(b.at(i)>=97&&b.at(i)<=122) b.at(i)-=87; c.at(i)=a.at(i)+b.at(i); } for(i=kmin;i<kmax+1;i++) { if(c.at(i)>=48&&c.at(i)<=57) c.at(i)-=48; if(c.at(i)>=97&&c.at(i)<=122) c.at(i)-=87; } for(i=0;i<kmax;i++) { if(c.at(i)>=n)  {  c.at(i+1)+=c.at(i)/n;  c.at(i)=c.at(i)%n; } } if(c.at(kmax)==0)  { c.erase(kmax,kmax+1); } for(i=0;i<c.length();i++) { if(c.at(i)>=10) c.at(i)+=87; if(c.at(i)<10) c.at(i)+=48; } reverse(c.begin(),c.end()); return c;}int main(){ string a,b; while(cin>>a>>b) { cout<<add(a,b); } return 0;}