python 計算兩個日期相差多少個月實例代碼

2020-01-04 17:13:04

字體：大中小

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供稿：網友

近期，由于業務需要計算兩個日期之前相差多少個月。我在網上找了很久，結果發現萬能的python/267134.html">python/107427.html">python，居然沒有一個模塊計算兩個日期的月數，像Java、C#之類的高級語言，都會有(date1-date2).months的現成方法，覺得不可思議。說句實在的，一直覺得python 的日期處理模塊真心不好用。

哦，對了，別跟我說 datetime, calendar, dateutil 這些模塊，因為我都試過了，都沒用。有個竟然算出來還有錯。datetime.timedelta只能計算出日時分秒。對年月卻不支持。網上一搜，一大堆的。

dateutil.rrule這個例子是我好不容易找到的，請看我的測試結果：

import datetimefrom dateutil import rruled1 = datetime.date(2016, 2, 29)d2 = datetime.date(2019, 3, 31)months = rrule.rrule(rrule.MONTHLY, dtstart=d1, until=d2).count()print(f"months={months}")

python,日期相差天數,相差月份,日期差多少月

看到這樣的結果，我只能呵呵了。

廢話不多少，獻上自己寫的代碼：

該代碼返回，（月,小數月）

import datetimeimport calendar as cd1 = datetime.date(2016, 2, 29)d2 = datetime.date(2019, 3, 31)def calmonths(startdate, enddate):# 計算兩個日期相隔月差samemonthdate = Nonetry:samemonthdate = datetime.date(enddate.year, enddate.month,startdate.day)except Exception as e:print(e)samemonthdate = datetime.date(enddate.year, enddate.month,c.monthrange(enddate.year,enddate.month)[1])holdmonths = 0decimalmonth = 0.0if samemonthdate > enddate:premanthdate = Nonetry:premanthdate = datetime.date(enddate.year, enddate.month - 1,startdate.day)except Exception as e:print(e)premanthdate = datetime.date(enddate.year, enddate.month - 1,c.monthrange(enddate.year,enddate.month - 1)[1])currmonthdays = (samemonthdate - premanthdate).daysholdmonths = (premanthdate.year - startdate.year) * 12 + premanthdate.month - startdate.monthdecimalmonth = (enddate - premanthdate).days / currmonthdayselif samemonthdate < enddate:nextmonthdate = Nonetry:nextmonthdate = datetime.date(enddate.year, enddate.month + 1,startdate.day)except Exception as e:nextmonthdate = datetime.date(enddate.year, enddate.month + 1,c.monthrange(enddate.year,enddate.month + 1)[1])currmonthdays = (nextmonthdate - samemonthdate).daysholdmonths = (samemonthdate.year - startdate.year) * 12 + samemonthdate.month - startdate.monthdecimalmonth = (enddate - samemonthdate).days / currmonthdayselse:holdmonths = (enddate.year - startdate.year) * 12 + enddate.month - startdate.monthreturn holdmonths, decimalmonthmonths = calmonths(d1, d2)print(f"months={months}")

python,日期相差天數,相差月份,日期差多少月