>>> re.findall(r"a(/d+?)","a23b") # 非貪婪模式    ['2']>>> re.findall(r"a(/d+)","a23b")    ['23']

>>> re.findall(r"a(/d+)b","a23b")    ['23']>>> re.findall(r"a(/d+?)b","a23b") #如果前后均有限定條件，則非匹配模式失效    ['23']

>>> re.findall(r"a(/d+)b.+a(/d+)b","a23b/na34b")    []>>> re.findall(r"a(/d+)b.+a(/d+)b","a23b/na34b",re.S)    [('23','34')]>>>

>>> re.findall(r"^a(/d+)b","a23b/na34b")    ['23']>>> re.findall(r"^a(/d+)b","a23b/na34b",re.M)    ['23','34']

>>> re.findall(r"a(/d+)b","a23b/na34b")    ['23','43']

import ren='''12 drummers drumming,11 pipers piping, 10 lords a-leaping'''p=re.compile('^/d+')p_multi=re.compile('^/d+',re.MULTILINE) #設置 MULTILINE 標志print re.findall(p,n) #['12']print re.findall(p_multi,n) # ['12', '11']

import rea = 'a23b'print re.findall('a(/d+?)',a) #['2']print re.findall('a(/d+)',a) #['23']print re.findall(r'a(/d+)b',a) #['23']print re.findall(r'a(/d+?)b',a) # ['23']

b='a23b/na34b'''' . 匹配非換行符的任意一個字符'''print re.findall(r'a(/d+)b.+a(/d+)b',b) #[]print re.findall(r'a(/d+)b',b,re.M) # ['23', '34']print re.findall(r'^a(/d+)b',b,re.M) # ['23', '34']print re.findall(r'a(/d+)b',b) #['23','34'] 可以匹配多行print re.findall(r'^a(/d+)b',b) # ['23'] 默認^只會匹配符合正則的第一行print re.findall(r'a(/d+)b$',b) # ['34'] 默認$只會匹配符合正則的末行print re.findall(r'a(/d+)b',b,re.M) #['23', '34']print re.findall(r'a(/d+)b.?',b,re.M) # ['23', '34'] 表達式中的'.'匹配除換行符以外的字符，'?'匹配前一個字符0次或1次print re.findall(r"a(/d+)b", "a23b/na34b") # ['23', '34']