常用的表達式操作符：x + y, x - yx * y, x / y, x // y, x % y邏輯運算：x or y, x and y, not x成員關系運算：x in y, x not in y對象實例測試：x is y, x not is y比較運算：x < y, x > y, x <= y, x >= y, x == y, x != y位運算：x | y, x & y, x ^ y, x << y, x >> y一元運算：-x, +x, ~x:冪運算：x ** y索引和分片：x[i], x[i:j], x[i:j:stride]調用：x(...)取屬性：  x.attribute元組：(...)序列：[...]字典：{...}三元選擇表達式：x if y else z匿名函數：lambda args: expression生成器函數發送協議：yield x 運算優先級：(...), [...], {...}s[i], s[i:j]s.attributes(...)+x, -x, ~xx ** y*, /, //, %+, -<<, >> &^|<, <=, >, >=, ==, !=is, not isin, not innotandorlambda 

賦值語句  調用  print： 打印對象  if/elif/else: 條件判斷  for/else: 序列迭代  while/else: 普通循環  pass: 占位符  break:   continue  def  return  yield  global: 命名空間  raise: 觸發異常  import:   from: 模塊屬性訪問  class: 類  try/except/finally: 捕捉異常  del: 刪除引用  assert: 調試檢查  with/as: 環境管理器  賦值語句：  隱式賦值：import, from, def, class, for, 函數參數  元組和列表分解賦值：當賦值符號(=)的左側為元組或列表時，Python會按照位置把右邊的對象和左邊的目標自左而右逐一進行配對兒；個數不同時會觸發異常，此時可以切片的方式進行；  多重目標賦值  增強賦值: +=, -=, *=, /=, //=, %=, 

練習1：逐一分開顯示指定字典d1中的所有元素，類似如下k1 v1k2 v2...    >>> d1 = { 'x':1,'y':2,'z':3,'m':4 }  >>> for (k,v) in d1.items():  print k,v   y 2  x 1  z 3  m 4    練習2：逐一顯示列表中l1=["Sun","Mon","Tue","Wed","Thu","Fri","Sat"]中的索引為奇數的元素；    >>> l1 = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"]  >>> for i in range(1,len(l1),2):  print l1[i]    Mon  Wed  Fri    練習3：將屬于列表l1=["Sun","Mon","Tue","Wed","Thu","Fri","Sat"]，但不屬于列表l2=["Sun","Mon","Tue","Thu","Sat"]的所有元素定義為一個新列表l3;     >>> l1 = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"]  >>> l2 = ["Sun","Mon","Tue","Thu","Sat"]  >>> l3 = [ ]  >>> for i in l1:  if i not in l2:l3.append(i)  >>> l3  ['Wed', 'Fri']     練習4：已知列表namelist=['stu1','stu2','stu3','stu4','stu5','stu6','stu7']，刪除列表removelist=['stu3', 'stu7', 'stu9']；請將屬于removelist列表中的每個元素從namelist中移除(屬于removelist，但不屬于namelist的忽略即可)；     >>> namelist= ['stu1','stu2','stu3','stu4','stu5','stu6','stu7']  >>> removelist = ['stu3', 'stu7', 'stu9']    >>> for i in namelist:  if i in removelist :namelist.remove(i)  >>> namelist  ['stu1', 'stu2', 'stu4', 'stu5', 'stu6']

練習1：逐一顯示指定列表中的所有元素；  >>> l1 = [1,2,3,4,5]  >>> i = 0  >>> while i < len(l1)  print l1[i]  i += 1    1  2  3  4  5  >>> l1 = [1,2,3,4,5]  >>> while l1:  print l1.pop(0)    1  2  3  4  5  練習2：求100以內所有偶數之和；    >>> i = 0  >>> sum = 0   >>> while i < 101:  sum += i  i += 2print sum    2550    >>> for i in range(0,101,2):  sum+=i   print sum    2550      練習3：逐一顯示指定字典的所有鍵；并于顯示結束后說明總鍵數；      >>> d1 = {'x':1, 'y':23, 'z': 78}  >>> i1 = d1.keys()  >>> while i1:  print i1.pop(0)else:  print len(d1)  x  y  z  3    練習4：創建一個包含了100以內所有奇數的列表；      >>> d1 = [ ]  >>> i = 1  >>> while i < 101:  d1.append(i)  i+=2  >>> print d1  [1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49, 51, 53, 55, 57, 59, 61, 63, 65, 67, 69, 71, 73, 75, 77, 79, 81, 83, 85, 87, 89, 91, 93, 95, 97, 99]      >>> d1 = [ ]   >>> for i in range(1,101,2)  d1.append(i)  >>> print d1  [1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49, 51, 53, 55, 57, 59, 61, 63, 65, 67, 69, 71, 73, 75, 77, 79, 81, 83, 85, 87, 89, 91, 93, 95, 97, 99]  練習5：列表l1=[0,1,2,3,4,5,6], 列表l2=["Sun","Mon","Tue","Wed","Thu","Fri","Sat"]，以第一個列表中的元素為鍵，以第二個列表中的元素為值生成字典d1；     >>> l1 = [0,1,2,3,4,5,6]   >>> l2 = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"]  >>> d1 = {}  >>> count = 0  >>> if len(l1) == len(l2):  while count < len(l1):d1[l1[count]] = l2[count] count += 1