divmod(a,b)函數(shù)
中文說明:
divmod(a,b)方法返回的是a//b(除法取整)以及a對b的余數(shù)
返回結(jié)果類型為tuple
參數(shù):
a,b可以為數(shù)字(包括復數(shù))
版本:
在python2.3版本之前不允許處理復數(shù),這個大家要注意一下
英文說明:
Take two (non complex) numbers as arguments and return a pair of numbers consisting of their quotient and remainder when using long division. With mixed operand types, the rules for binary arithmetic operators apply. For plain and long integers, the result is the same as (a // b, a % b). For floating point numbers the result is (q, a % b), where q is usually math.floor(a / b) but may be 1 less than that. In any case q * b + a % b is very close to a, if a % b is non-zero it has the same sign as b, and 0 <= abs(a % b) < abs(b).
Changed in version 2.3: Using divmod() with complex numbers is deprecated.
python代碼實例:
>>> divmod(9,2)(4, 1)>>> divmod(11,3)(3, 2)>>> divmod(1+2j,1+0.5j)((1+0j), 1.5j)
PS:Python標準庫:內(nèi)置函數(shù)divmod(a, b)
本函數(shù)是實現(xiàn)a除以b,然后返回商與余數(shù)的元組。如果兩個參數(shù)a,b都是整數(shù),那么會采用整數(shù)除法,結(jié)果相當于(a//b, a % b)。如果a或b是浮點數(shù),相當于(math.floor(a/b), a%b)。
例子:
#divmod() print('divmod(2, 4):', divmod(2, 4)) print('divmod(28, 4):', divmod(28, 4)) print('divmod(27, 4):', divmod(27, 4)) print('divmod(25.6, 4):', divmod(25.6, 4)) print('divmod(2, 0.3):', divmod(2, 0.3)) 輸出結(jié)果如下:
divmod(2, 4): (0, 2)divmod(28, 4): (7, 0)divmod(27, 4): (6, 3)divmod(25.6, 4): (6.0, 1.6000000000000014)divmod(2, 0.3): (6.0, 0.20000000000000007)
總結(jié)
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