本文實例為大家分享了python3判斷url鏈接是否為404的具體代碼,供大家參考,具體內容如下
import pymysqlimport threadingimport timeimport urllibimport requests # 打開數據庫連接db = pymysql.connect("192.168.0.*", "username", "password", "databasename")# 使用 cursor() 方法創建一個游標對象 cursorcursor = db.cursor()# SQL 查詢語句sql = "SELECT sku,url_6 FROM url_new where flag_6 is null and url_6<>'' " # 執行SQL語句cursor.execute(sql) # 獲取所有記錄列表results = cursor.fetchall()num = 0for row in results: sku = row[0] url = row[1] html = requests.head(url) # 用head方法去請求資源頭 re=html.status_code num = num + 1 print(num,re) if re == 200: sql_2 = "UPDATE url_new SET flag_6 = 0 WHERE sku = '%s'" % sku try: # 執行SQL語句 cursor.execute(sql_2) #print(cursor.rowcount) except Exception as e: print(e) conn.rollback() if re == 404: sql_3 = "UPDATE url_new SET flag_6 = 1 WHERE sku = '%s'" % sku try: # 執行SQL語句 cursor.execute(sql_3) print(cursor.rowcount) except Exception as e: print(e) conn.rollback() db.commit()db.close()以上就是本文的全部內容,希望對大家的學習有所幫助,也希望大家多多支持VEVB武林網。
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