>>> li = [1,2,3,4,5,6]# 求元素的平方>>> li_a = [x**2 for x in li ]>>> li_a[1, 4, 9, 16, 25, 36]# 提取偶數(shù)值>>> li_b = [x for x in li if x%2==0]>>> li_b[2, 4, 6]# 將多維數(shù)組轉(zhuǎn)換成一維數(shù)組>>> li_c = [[1,2], [3], [], [4,5,6]]>>> li_d = [j for i in li_c for j in i ]>>> li_d[1, 2, 3, 4, 5, 6]# 使用map>>> li_1 = ['a', 'b', 'c', 'd']>>> li_2 = [10, 20, 30, 40]>>> li_e = list(map(lambda x, y:{x:y}, li_1, li_2))>>> li_e[{'a': 10}, {'b': 20}, {'c': 30}, {'d': 40}]

# 解析列表>>> li = ['a', 'b', 'c', 'd', 'e']>>> li_1 = {k:v for k, v in enumerate(li)}>>> li_1{0: 'a', 1: 'b', 2: 'c', 3: 'd', 4: 'e'}# 解析字典>>> dict_a = {'a':10, 'b':20, 'c':30}>>> dict_b = {v:k for k, v in dict_a.items()}>>> dict_b{10: 'a', 20: 'b', 30: 'c'}

>>> set1 = {x for x in range(10)}>>> set1set([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])