package testsource;  import java.util.ArrayList; import java.util.List;  /**  *  * @author Waston Xu  * @date 2011-4-15 上午10:48:21  */ public class MyString implements Comparable<MyString> {   private final String string;   private List<Object> list;    public MyString(String string) {     this.string = string;     trimString2List();   }    private void trimString2List() {     list = new ArrayList<Object>();     Integer num = 0;     StringBuffer sb = new StringBuffer();     for (int i = 0; i < this.string.length(); i++) {       char c = this.string.charAt(i);       if (c > 47 && c < 58) {         if (sb.length() != 0) {           list.add(sb);           sb = new StringBuffer();         }         num = num * 10 + (c - '0');         continue;       } else {         if (num != 0) {           list.add(num);           num = 0;         }         sb.append(c);         continue;       }     }     if (sb.length() != 0) {       list.add(sb);       sb = new StringBuffer();     } else if (num != 0) {       list.add(num);       num = 0;     }   }    /*    * 在仔細的觀看了String的compareTo方法后，本來打算不調用其API進行編程，    * 但是考慮到出現"a02"和"a2"這樣的情況還是使用其API中的方式解決。    */   private int compareToLikeString(String s) {     int len1 = string.length();     int len2 = s.length();     int n = Math.min(len1, len1);     if (n > 0) {       int k = 0;       while (k < n) {         char c1 = string.charAt(k);         char c2 = s.charAt(k);         if (c1 != c2)           return c1 - c2;         k++;       }     }      return len1 - len2;   }    @Override   public int compareTo(MyString anotherString) {     int len1 = list.size();     int len2 = anotherString.list.size();     int n = Math.min(len1, len2);      int mark = 0;     if (n > 0) {       int i = 0;       while (i < n) {         Object o1 = list.get(i);         Object o2 = anotherString.list.get(i);         if (o1 instanceof Integer && o2 instanceof Integer) {           mark = (Integer) o1 - (Integer) o2;         } else {           mark = o1.toString().compareTo(o2.toString());         }         if (mark != 0)           return mark;         i++;       }     }     return compareToLikeString(anotherString.string);     //return string.compareTo(anotherString.string);     /* 如果這樣寫會有個弊端就是出現"a02"和"a2"這樣的情況，肯定是前面的小*/     //return string.length() - anotherString.string.length();   }    public static void main(String[] args) {     String s1 = "b9c";     String s2 = "b09c";     MyString m1 = new MyString(s1);     MyString m2 = new MyString(s2);      System.out.println(m1.compareTo(m2));   } }