java中實現list或set轉map的方法
在開發中我們有時需要將list或set轉換為map（比如對象屬性中的唯一鍵作為map的key，對象作為map的value），一般的想法就是new一個map，然后把list或set中的值一個個push到map中。
類似下面的代碼：
List<String> stringList = Lists.newArrayList("t1", "t2", "t3"); Map<String, String> map = Maps.newHashMapWithExpectedSize(stringList.size()); for (String str : stringList) { map.put(str, str); } 是否還有更優雅的寫法呢？答案是有的。
guava提供了集合（實現了Iterables接口或Iterator接口）轉map的方法，方法定義如下：
/** * Returns an immutable map for which the {@link Map#values} are the given * elements in the given order, and each key is the product of invoking a * supplied function on its corresponding value. * * @param values the values to use when constructing the {@code Map} * @param keyFunction the function used to produce the key for each value * @return a map mapping the result of evaluating the function {@code * keyFunction} on each value in the input collection to that value * @throws IllegalArgumentException if {@code keyFunction} produces the same * key for more than one value in the input collection * @throws NullPointerException if any elements of {@code values} is null, or * if {@code keyFunction} produces {@code null} for any value */ public static <K, V> ImmutableMap<K, V> uniqueIndex( Iterable<V> values, Function<? super V, K> keyFunction) { return uniqueIndex(values.iterator(), keyFunction); } /** * Returns an immutable map for which the {@link Map#values} are the given * elements in the given order, and each key is the product of invoking a * supplied function on its corresponding value. * * @param values the values to use when constructing the {@code Map} * @param keyFunction the function used to produce the key for each value * @return a map mapping the result of evaluating the function {@code * keyFunction} on each value in the input collection to that value * @throws IllegalArgumentException if {@code keyFunction} produces the same * key for more than one value in the input collection * @throws NullPointerException if any elements of {@code values} is null, or * if {@code keyFunction} produces {@code null} for any value * @since 10.0 */ public static <K, V> ImmutableMap<K, V> uniqueIndex( Iterator<V> values, Function<? super V, K> keyFunction) { checkNotNull(keyFunction); ImmutableMap.Builder<K, V> builder = ImmutableMap.builder(); while (values.hasNext()) { V value = values.next(); builder.put(keyFunction.apply(value), value); } return builder.build(); } 這樣我們就可以很方便的進行轉換了，如下：
List<String> stringList = Lists.newArrayList("t1", "t2", "t3"); Map<String, String> map = Maps.uniqueIndex(stringList, new Function<String, String>() { @Override public String apply(String input) { return input; } }); 需要注意的是，如接口注釋所說，如果Function返回的結果產生了重復的key，將會拋出異常。
java8也提供了轉換的方法，這里直接照搬別人博客的代碼：
@Test public void convert_list_to_map_with_java8_lambda () { List<Movie> movies = new ArrayList<Movie>(); movies.add(new Movie(1, "The Shawshank Redemption")); movies.add(new Movie(2, "The Godfather")); Map<Integer, Movie> mappedMovies = movies.stream().collect( Collectors.toMap(Movie::getRank, (p) -> p)); logger.info(mappedMovies); assertTrue(mappedMovies.size() == 2); assertEquals("The Shawshank Redemption", mappedMovies.get(1).getDescription()); } 新聞熱點
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