搜索了好幾個python實現的萬年歷多有部分時間有問題，好多是來自這個代碼：
This Python script is to show Solar and Lunar calender at the
same time. You need to have Python (2.0 or above) installed.
Acceptable date range: 1900/2 -- 2049/12
Output contains Chinese characters (mainland GB2312 encoding),
must be viewed in a Chinese-enabled system or "cxterm" etc.
programms under UNIX X-Windows.
The major reference for me to compose this program is:
lunar-2.1.tgz (1992), composed by
Fung F. Lee <lee@umunhum.stanford.edu> and
Ricky Yeung <Ricky.Yeung@Eng.Sun.Com> .
And Lee and Yeung refered to:
1. "Zhong1guo2 yin1yang2 ri4yue4 dui4zhao4 wan4nian2li4"
by Lin2 Qi3yuan2. 《中國陰陽日月對照萬年歷》．林
2. "Ming4li3 ge2xin1 zi3ping2 cui4yan2" by Xu2 Le4wu2.
《命理革新子平粹言》．徐
3. Da1zhong4 wan4nian2li4. 《大眾萬年歷》
License:
GNU General Public License (GPL, see http://www.gnu.org).
In short, users are free to use and distribute this program
in whole. If users make revisions and distribute the revised
one, they are required to keep the revised source accessible
to the public.
Version:
0.3.2, Jan/16/2007, according to sprite's information, changed 3 codes:
1954: 0x0a5d0 --> 0x0a5b0, 1956: 0x052d0 --> 0x052b0
1916: 0x0d6a0 --> 0x056a0
0.3.1, Jan/15/2007, changed 1978's code from 0xb5a0 to 0xb6a0.
A young lady's birth day (lunar 1978/8/4) problem reported
on internet -- informed by sprite at linuxsir.org
0.3.0, Sep/25/2006, add coding line, prevent python to report warning
0.2.0, Jan/6/2002, ShengXiao(生肖), lunar leap month(閏月)
added.
0.1.0, Jan/4/2002
--- Changsen Xu <xucs007@yahoo.com>
'''
#Remember, in this program:
# month=0 means Januaray, month=1 means February ...;
# day=0 means the first day of a month, day=1 means the second day,
# so as to ease manipulation of Python lists.
# year=0 is 1900, until the last step to output
daysInSolarMonth= [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
lunarMonthDays = [29,30] # a short (long) lunar month has 29 (30) days */
shengXiaoEn = ["Mouse", "Ox", "Tiger", "Rabbit", "Dragon", "Snake",
"Horse", "Goat", "Monkey", "Rooster", "Dog", "Pig"]
shengXiaoGB = ["鼠", "牛", "虎", "兔", "龍", "蛇", "馬", "羊", "猴", "雞",
"狗", "豬"]
zhiGB = ["子", "丑", "寅", "卯", "辰", "巳", "午", "未", "申", "酉",
"戌", "亥"]
ganGB = ["甲", "乙", "丙", "丁", "戊", "己", "庚", "辛", "壬", "癸"]
monthEn = ['January', 'February', 'March', 'April', 'May', 'June',
'July', 'August', 'September', 'October', 'November',
'December']
weekdayEn = ["Monday", "Tuesday", "Wednesday", "Thursday",
"Friday", "Saturday", "Sunday"]
weekdayGB = ["一", "二", "三", "四", "五", "六", "日"]
numGB = ['○', "一", "二", "三", "四", "五", "六", "七", "八", "九",
"十"]
lunarHoliday = {'0_0':'春節', '4_4':'端午', '7_14':'中秋', '8_8':'重陽',
'0_14':'元宵'}
# encoding:
# b bbbbbbbbbbbb bbbb
# bit# 1 111111000000 0000
# 6 543210987654 3210
# . ............ ....
# month# 000000000111
# M 123456789012 L
#
# b_j = 1 for long month, b_j = 0 for short month
# L is the leap month of the year if 1<=L<=12; NO leap month if L = 0.
# The leap month (if exists) is long one if M = 1.
yearCode = [
0x04bd8, # 1900
0x04ae0, 0x0a570, 0x054d5, 0x0d260, 0x0d950, # 1905
0x16554, 0x056a0, 0x09ad0, 0x055d2, 0x04ae0, # 1910
0x0a5b6, 0x0a4d0, 0x0d250, 0x1d255, 0x0b540, # 1915
0x056a0, 0x0ada2, 0x095b0, 0x14977, 0x04970, # 1920
0x0a4b0, 0x0b4b5, 0x06a50, 0x06d40, 0x1ab54, # 1925
0x02b60, 0x09570, 0x052f2, 0x04970, 0x06566, # 1930
0x0d4a0, 0x0ea50, 0x06e95, 0x05ad0, 0x02b60, # 1935
0x186e3, 0x092e0, 0x1c8d7, 0x0c950, 0x0d4a0, # 1940
0x1d8a6, 0x0b550, 0x056a0, 0x1a5b4, 0x025d0, # 1945
0x092d0, 0x0d2b2, 0x0a950, 0x0b557, 0x06ca0, # 1950
0x0b550, 0x15355, 0x04da0, 0x0a5b0, 0x14573, # 1955
0x052b0, 0x0a9a8, 0x0e950, 0x06aa0, 0x0aea6, # 1960
0x0ab50, 0x04b60, 0x0aae4, 0x0a570, 0x05260, # 1965
0x0f263, 0x0d950, 0x05b57, 0x056a0, 0x096d0, # 1970
0x04dd5, 0x04ad0, 0x0a4d0, 0x0d4d4, 0x0d250, # 1975
0x0d558, 0x0b540, 0x0b6a0, 0x195a6, 0x095b0, # 1980
0x049b0, 0x0a974, 0x0a4b0, 0x0b27a, 0x06a50, # 1985
0x06d40, 0x0af46, 0x0ab60, 0x09570, 0x04af5, # 1990
0x04970, 0x064b0, 0x074a3, 0x0ea50, 0x06b58, # 1995
0x055c0, 0x0ab60, 0x096d5, 0x092e0, 0x0c960, # 2000
0x0d954, 0x0d4a0, 0x0da50, 0x07552, 0x056a0, # 2005
0x0abb7, 0x025d0, 0x092d0, 0x0cab5, 0x0a950, # 2010
0x0b4a0, 0x0baa4, 0x0ad50, 0x055d9, 0x04ba0, # 2015
0x0a5b0, 0x15176, 0x052b0, 0x0a930, 0x07954, # 2020
0x06aa0, 0x0ad50, 0x05b52, 0x04b60, 0x0a6e6, # 2025
0x0a4e0, 0x0d260, 0x0ea65, 0x0d530, 0x05aa0, # 2030
0x076a3, 0x096d0, 0x04bd7, 0x04ad0, 0x0a4d0, # 2035
0x1d0b6, 0x0d250, 0x0d520, 0x0dd45, 0x0b5a0, # 2040
0x056d0, 0x055b2, 0x049b0, 0x0a577, 0x0a4b0, # 2045
0x0aa50, 0x1b255, 0x06d20, 0x0ada0 # 2049
]
yearsCoded = len(yearCode)
from sys import argv, exit, stdout
from time import time, localtime
ow=stdout.write
class LunarYearInfo:
def __init__(self):
self.yearDays = 0
self.monthDays = [0]*13
self.leapMonth = -1 # -1 means no lunar leap month
yearInfo = [0]*yearsCoded #global variable
for i in range(yearsCoded):
yearInfo[i] = LunarYearInfo()
class Date:
def __init__(self, year, month, day, weekday=-1, gan=-1, zhi=-1):
self.year =year
self.month =month
self.day =day
self.weekday=weekday
self.gan =gan
self.zhi =zhi
solar1st = Date(0, 0, 30, weekday=2) #Wednesday, January 31, 1900
lunar1st = Date(0, 0, 0, weekday=2, gan=6, zhi=0)
#Wednesday, First day, First month, 1900, 庚子年
def error(msg):
print 'Error:', msg; exit(0)
def isSolarLeapYear (year):
year=year+1900
return (year%4 == 0) and (year%100 != 0) or (year%400 == 0)
baseYear=1201 - 1900
# in fact, real baseYear=1201. In order to ease calculation of
# leap years. real baseYear must conform to:
# realBaseYear%4==1 and realBaseYear%400==1.
# Assert realBaseYear < solar1st.year .
# Compute the number of days from the Solar First Date
# month=0 means January, ...
def solarDaysFromBaseYear(d): #d is a Date class
delta = d.year - baseYear
offset = delta*365 + delta/4 - delta/100 + delta/400
for i in range(d.month):
offset += daysInSolarMonth[i];
if d.month>1 and isSolarLeapYear(d.year):
offset += 1
offset += d.day
## print '___', year, month, day, 'offset=', offset ########
return offset
# Compute the number of days from the Solar First Date
# month=0 means January, ..., year=0 means 1900, ...
def solarDaysFromFirstDate (d): #d is a Date class
return solarDaysFromBaseYear (d) - solarDaysFromBaseYear (solar1st)
def calcLunarDaysPerMonth(iYear):
code = yearCode[iYear]
leapMonth = code&0xf #leapMonth==0 means no lunar leap month
code >>= 4
for iMonth in range(12):
yearInfo[iYear].monthDays[11-iMonth] = lunarMonthDays [code&0x1]
code >>= 1
if leapMonth>0:
yearInfo[iYear].leapMonth = leapMonth-1
yearInfo[iYear].monthDays.insert (leapMonth,
lunarMonthDays [code & 0x1])
def calcAllLunarYearsInfo():
for iYear in range(yearsCoded):
calcLunarDaysPerMonth (iYear)
for iMonth in range(13):
yearInfo[iYear].yearDays += yearInfo[iYear].monthDays[iMonth]
#input dateSolar, return (dateLunar, isLunarMonthOrNot)
def solar2Lunar(d): #d is a Date class
dLunar = Date(-1, -1, -1) #unknown lunar Date class
offset = solarDaysFromFirstDate(d)
dLunar.weekday = (offset + solar1st.weekday)%7
for iYear in range(yearsCoded):
if offset < yearInfo[iYear].yearDays:
dLunar.year = iYear; break
offset -= yearInfo[iYear].yearDays
if dLunar.year == -1: error ("Date out of range.")
dLunar.gan = (dLunar.year + lunar1st.gan) % 10
dLunar.zhi = (dLunar.year + lunar1st.zhi) % 12
for iMonth in range(13):
if offset< yearInfo[dLunar.year].monthDays[iMonth]:
dLunar.month = iMonth; break
offset -= yearInfo[dLunar.year].monthDays[iMonth]
dLunar.day = offset
isLeapMonth=0
if yearInfo[dLunar.year].leapMonth >=0:
if dLunar.month == yearInfo[iYear].leapMonth + 1:
isLeapMonth=1
if dLunar.month > yearInfo[dLunar.year].leapMonth:
dLunar.month -= 1
return (dLunar, isLeapMonth)
def getSolarDaysInMonth (year, month):
if isSolarLeapYear(year) and month==1:
return 29
else: return daysInSolarMonth[month]
def num2GB (num):
if num==10:
return '十'
elif num>10 and num<20:
return '十' + numGB[num-10]
tmp=''
while num>10:
tmp = numGB[num%10] + tmp
num = int(num/10)
tmp = numGB[num] + tmp
return tmp
def lunarDate2GB (dLunar, isLeapMonth):
tmp = str(dLunar.month)+'_'+str(dLunar.day)
if lunarHoliday.has_key( tmp ):
return '[0;33;44m%s[0m '% lunarHoliday[tmp] + /
' '*(6-len(lunarHoliday[tmp]))
elif dLunar.day==0:
tmp2 = '閏'*isLeapMonth + num2GB(dLunar.month+1) +'月'
return '[7m%s[0m' % tmp2 + ' '*(8-len(tmp2))
elif dLunar.day<10:
return '初' + num2GB(dLunar.day+1)
else:
return num2GB(dLunar.day+1)
def outputCalendar(year, month):
dLunar = Date(-1,-1,-1)
ow ('/n 陽歷%d年%d月 ' % (year+1900, month+1) )
for iDay in range( getSolarDaysInMonth(year, month) ):
dSolar = Date(year, month, iDay)
dLunar, isLeapMonth = solar2Lunar (dSolar)
if iDay==0:
ow ('始于 陰歷%s年%s%s月 (%s%s年, 生肖屬%s)/n' %
( num2GB(dLunar.year+1900), '閏'*isLeapMonth,
num2GB(dLunar.month+1),
ganGB [dLunar.gan], zhiGB[dLunar.zhi], shengXiaoGB[dLunar.zhi]
))
ow ('='*74 + '/n')
for i in range(7):
ow ("%3s %2s " % (weekdayEn[i][:3], weekdayGB[i]) )
ow('/n/n')
for i in range(dLunar.weekday): ow(' '*11)
elif dLunar.weekday==0: ow('/n')
ow ( "%2d %-8s" %(iDay+1, lunarDate2GB(dLunar, isLeapMonth) ) )
ow('/n/n')
def checkArgv (argv):
argc = len(argv)
if argc==1 or argv[1] in ('-h', '--help'):
print __doc__; exit(0)
#in case people input arguments as "4-digit-year month"
if argc==3 and len(argv[1]) == 4 and len(argv[2]) in (1,2):
argv[1], argv[2] = argv[2], argv[1]
#Get month
month=-1
for iMonth in range(12):
if argv[1].lower() == monthEn[iMonth].lower() or /
argv[1].lower() == monthEn[iMonth][:3].lower():
month = iMonth+1; break
if month==-1:
month = eval(argv[1])
if month<1 or month>12: error ("Month not within 1--12.")
#Get year
if argc==2: year = localtime(time())[0]
else:
if len(argv[2]) != 4: error ("Year must be 4 digits.")
year = eval(argv[2])
if year<1900 or year>= 1900+yearsCoded or (year==1900 and month==1):
error ("Year must be within %d--%d, excluding 1900/1."
% (1900, 1900 + yearsCoded-1) )
return year-1900, month-1
year, month = checkArgv(argv)
calcAllLunarYearsInfo()
outputCalendar(year, month)
這個也有問題（1989年8月的數據轉換成農歷就有問題）
看了好幾個程序，發現實現這個并不需要什么NB的算法（好像也不存在這樣的算法）可以直接實現陽歷轉為陰歷的，都是記錄了一堆陰歷的數據，然后根據和基本時間來算相差幾天來計算的，所有陰歷數據的正確性決定了這個程序的正確性。
同學給了一個lua的程序，我試了一下，還沒有找到錯誤的，先直接給上程序（直接從lua轉成python的，寫的比較亂）