python 的 zipfile 提供了非常便捷的方法來壓縮和解壓 zip 文件。
例如,在py腳本所在目錄中,有如下文件:
readability/readability.jsreadability/readability.txtreadability/readability-print.cssreadability/sprite-readability.pngreadability/readability.css
將 readability 目錄中的文件壓縮到腳本所在目錄的 readability.zip 文件中,保持相同的文件結(jié)構(gòu),然后打印出生成的壓縮包 的文件列表,再用兩種方式分別解壓文件到腳本所在目錄的 output 目錄和 output/bak 目錄中。
腳本如下:
#!/usr/vin/env python# coding: utf-8"""壓縮和解壓zip文件"""import osimport zipfiledef compress(zip_file, input_dir): f_zip = zipfile.ZipFile(zip_file, 'w') for root, dirs, files in os.walk(input_dir): for f in files: # 獲取文件相對(duì)路徑,在壓縮包內(nèi)建立相同的目錄結(jié)構(gòu) abs_path = os.path.join(os.path.join(root, f)) rel_path = os.path.relpath(abs_path, os.path.dirname(input_dir)) f_zip.write(abs_path, rel_path, zipfile.ZIP_STORED)def extract(zip_file, output_dir): f_zip = zipfile.ZipFile(zip_file, 'r') # 解壓所有文件到指定目錄 f_zip.extractall(output_dir) # 逐個(gè)解壓文件到指定目錄 for f in f_zip.namelist(): f_zip.extract(f, os.path.join(output_dir, 'bak'))def printdir(zip_file): f_zip = zipfile.ZipFile(zip_file, 'r') print '== printdir() ============================' f_zip.printdir() print print '== namelist() ============================' for f in f_zip.namelist(): print fif __name__ == '__main__': zip_file = 'readability.zip' compress(zip_file, os.path.join(os.getcwd(), 'readability')) printdirzip_file) extract(zip_file, 'output')</pre>
python暴力破解含密碼的zip壓縮文件
思路:
1.先自己生成一份txt的密碼字典
2.然后讀取出來,一個(gè)個(gè)的嘗試,當(dāng)密碼錯(cuò)誤是,程序會(huì)報(bào)錯(cuò)中斷,所以密碼錯(cuò)誤,要使用pass
3.當(dāng)解壓縮成功后,中斷程序,輸出正確密碼
import zipfileimport osfrom threading import Threadimport time#壓縮文件的路徑path = r'C:/Users/Administrator/Desktop/moeMaid-master.zip'#password='1234'def pojie_zip(path,password): if path[-4:]=='.zip': #path = dir+ '//' +file #print path zip = zipfile.ZipFile(path, "r",zipfile.zlib.DEFLATED) #print zip.namelist() try: #若解壓成功,則返回True,和密碼 zip.extractall(path='C://Users//Administrator//Desktop//',members=zip.namelist() , pwd=password) print ' ----success!,The password is %s' % password zip.close() return True except: pass #如果發(fā)生異常,不報(bào)錯(cuò) print 'error' def get_pass(): #密碼字典的路徑 passPath='C://Users//Administrator//Desktop//zip.txt' passFile=open(passPath,'r') for line in passFile.readlines(): password=line.strip('/n') print 'Try the password %s' % password if pojie_zip(path,password): break passFile.close()if __name__=='__main__': start=time.clock() get_pass() print "done (%.2f seconds)" % (time.clock() - start)
這是我解壓縮一個(gè)5.4M文件的速度,其實(shí)時(shí)間都花在了解壓縮上了
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