把字符串按照特定的字母順序進行排序的js代碼

2019-11-20 21:11:02

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來源：轉載

供稿：網友

例如，給一個特定的字母順序，"a","o","e","u","y","i"，請把'aiye','oeu','ayo','eoyiu','yuo','you','iao'這7個字符串按照給定的字母順序排序。

我的思路是把那幾個給定的6個字母分別等效成0-5的數字，然后把那7個字符串中的字母替換成0-5中的數字，再用sort方法進行排序，代碼如下：

復制代碼代碼如下:

 
var word = ['aiye','oeu','ayo','eoyiu','yuo','you','iao']; 
var obj = {a:0,o:1,e:2,u:3,y:4,i:5}; 
var obj1 = {0:'a',1:'o',2:'e',3:'u',4:'y',5:'i'}; 
for(var index in word){ 
var word1 = word[index]; 
var word3 = ""; 
for(var i = 0; i< word1.length; i ++ ){ 
word3 += obj[word1[i]]; 
}; 
word[index] = word3 
} 
word.sort(); 
for(var index in word){ 
var word1 = word[index]; 
var word3 = ""; 
for(var i = 0; i< word1.length; i ++ ){ 
word3 += obj1[word1[i]]; 
}; 
word[index] = word3 
} 
console.log(word); 

復制代碼代碼如下:

 
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