PROBLEM: ajackson@keck.tamu.edu (Andrew J. Jackson)
I'm inquiring on how to declare a reference to an array of integers
RESPONS: Efim Birger (efim@microware.com)
try this:
typedef int *intp; int arr[10]; intp& aaa = arr;
RESPONSE: fjh@munta.cs.mu.OZ.AU (Fergus Henderson), 11 Aug 94
This code is illegal. `aaa' is a (non-const) reference to a pointer to int. `arr' is an array of int, which will be converted to a pointer to int. The result of that conversion is a temporary. You are initializing a non-const reference with a temporary, which is illegal.
