描述：

　　　現(xiàn)在，有一行括號(hào)序列，請(qǐng)你檢查這行括號(hào)是否配對(duì)。

輸入:

第一行輸入一個(gè)數(shù)N（0<N<=100）,表示有N組測(cè)試數(shù)據(jù)。后面的N行輸入多組輸入數(shù)據(jù)，每組輸入數(shù)據(jù)都是一個(gè)字符串S(S的長(zhǎng)度小于10000，且S不是空串），測(cè)試數(shù)據(jù)組數(shù)少于5組。數(shù)據(jù)保證S中只含有"[","]","(",")"四種字符

輸出:

每組輸入數(shù)據(jù)的輸出占一行，如果該字符串中所含的括號(hào)是配對(duì)的，則輸出Yes,如果不配對(duì)則輸出No

樣例輸入：

3[(])(])([[]()])

樣例輸出：

NoNoYes

---

import java.util.Scanner;public class No2 {    PRivate String checkout(String str) {        try {            StringBuffer asb = new StringBuffer(str);  // 模擬棧A            StringBuffer bsb = new StringBuffer();   // 模擬棧B            int length = asb.length();            while (length > 0) {                // 遇右括號(hào)，移A入B                if (asb.charAt(length - 1) == ')'                        || asb.charAt(length - 1) == ']') {                    bsb.append(asb.charAt(length - 1));                    asb.deleteCharAt(length - 1);                    length = asb.length();                    continue;                }                // 遇左括號(hào)，若無(wú)法與B中棧頂元素合法匹配，則序列非法；若合法匹配，移A移B                if (asb.charAt(length - 1) == '(') {                    if (bsb.charAt(bsb.length() - 1) != ')') {                        return "No";                    } else {                        asb.deleteCharAt(asb.length() - 1);                        bsb.deleteCharAt(bsb.length() - 1);                        length = asb.length();                        continue;                    }                }                if (asb.charAt(length - 1) == '[') {                    if (bsb.charAt(bsb.length() - 1) != ']') {                        return "No";                    } else {                        asb.deleteCharAt(asb.length() - 1);                        bsb.deleteCharAt(bsb.length() - 1);                        length = asb.length();                        continue;                    }                }            }            if (bsb.length() == 0) {                return "Yes";            }        } catch (RuntimeException e) {        }        return "No";    }    public static void main(String args[]) throws Exception {        try {            Scanner cin = new Scanner(System.in);            int num = cin.nextInt();            String[] result = new String[num];            No2 no2 = new No2();            for (int i = 0; i < num; i++) {                String str = cin.next();                result[i] = no2.checkout(str);            }            for (int i = 0; i < num; i++) {                System.out.println(result[i]);            }        } catch (RuntimeException e) {        }    }}