2014-12-09

17:42:20

　　系統給定一個四位數。您有5次猜數機會，每次您可輸入一個四位數，系統判斷后會給出一個字符串，字符串由T、F、C表示。T表示該位上的數字是正確的；C表示該位上的數字存在這個四位數中，但位置錯誤；F表示該位上的數字是錯誤的，即不存在這個四位數中。

　　程序代碼如下：

 1 /**  2  * @author nlee 3  * @version 2:58:11 PM Dec 9, 2014 4  */ 5 package guessNum; 6  7 import java.util.Scanner; 8  9 public class GuessNum10 {11     public static void main(String[] args)12     {13         // 1.生成正確答案14         String correctAnswer = "";15         // 生成四個一位隨機數，并將其轉換成String類型16         for (int i = 0; i < 4; i++)17         {18             int a = (int) (Math.random() * 10);19             correctAnswer += a;20         }21         // System.out.PRintln(correctAnswer);22 23         Scanner in = new Scanner(System.in);24         // 輸入上限為5次25         int times = 5;26         for (int j = 0; j < times; j++)27         {28             System.out.println("You have " + (times - j) + " times, "29                     + "please entry your number(four figures):");30             // 2.輸入猜測的數字31             String num = in.next();32             // num與correctAnswer的比較結果33             String implynum = "";34             // 3.比較num與correctAnswer35             for (int i = 0; i < 4; i++)36             {37                 if (correctAnswer.charAt(i) == num.charAt(i))38                 {39                     implynum += "T";40                 }41                 else42                     // 判斷correctAnswer是否包含num.charAt(i)這個數字43                     if (correctAnswer.contains(((CharSequence) ("" + num44                             .charAt(i)))))45                     {46                         implynum += "C";47                     }48                     else49                     {50                         implynum += "F";51                     }52             }53             System.out.println(implynum);54             // 如果implynum等于“TTTT”，表明猜對了，結束循環55             if (implynum.equals("TTTT"))56             {57                 System.out58                         .println("/nCorrect Answer!/nCongratulations!/nYou have succeed!");59                 break;60             }61             else62                 // 如果implynum不等于“TTTT”， 并且猜測次數也達到上限，表明游戲失敗63                 if (j == (times - 1))64                 {65                     System.out.println("/nYou have failed!/nGame over!");66                     System.out.println("/nCorrect Answer is: " + correctAnswer);67                 }68                 else69                 {70                     System.out.println("Wrong Answer!/nPlease try again!/n");71                 }72         }73     }74 }