Splits this string around matches of the given regular exPRession.
This method works as if by invoking the two-argument split method with the given expression and a limit argument of zero. Trailing empty strings are therefore not included in the resulting array.
The string "boo:and:foo", for example, yields the following results with these expressions:
Regex Result : { "boo", "and", "foo" } o { "b", "", ":and:f" }
(1)如果用“.”作為分隔的話必須是如下寫法String.split("http://."),這樣才
能正確的分隔開不能用String.split(".");
比如這段代碼:
String str="123.456";String []arrStr=str.split(".");System.out.println(arrStr.length);結(jié)果為:

而:
String str="123.456";String []arrStr=str.split("http://.");System.out.println(arrStr.length);結(jié)果為:

原因是
Splits this string around matches of the givenregular expression.要求的是一個(gè)正則表達(dá)式所以必須滿足正則表達(dá)式的形式,
因此需要進(jìn)行轉(zhuǎn)義才行。
下面給出split()函數(shù)的源代碼供參考:
public String[] split(String regex, int limit) { /* fastpath if the regex is a (1)one-char String and this character is not one of the RegEx's meta characters ".$|()[{^?*+//", or (2)two-char String and the first char is the backslash and the second is not the ascii digit or ascii letter. */ char ch = 0; if (((regex.value.length == 1 && ".$|()[{^?*+//".indexOf(ch = regex.charAt(0)) == -1) || (regex.length() == 2 && regex.charAt(0) == '//' && (((ch = regex.charAt(1))-'0')|('9'-ch)) < 0 && ((ch-'a')|('z'-ch)) < 0 && ((ch-'A')|('Z'-ch)) < 0)) && (ch < Character.MIN_HIGH_SURROGATE || ch > Character.MAX_LOW_SURROGATE)) { int off = 0; int next = 0; boolean limited = limit > 0; ArrayList<String> list = new ArrayList<>(); while ((next = indexOf(ch, off)) != -1) { if (!limited || list.size() < limit - 1) { list.add(substring(off, next)); off = next + 1; } else { // last one //assert (list.size() == limit - 1); list.add(substring(off, value.length)); off = value.length; break; } } // If no match was found, return this if (off == 0) return new String[]{this}; // Add remaining segment if (!limited || list.size() < limit) list.add(substring(off, value.length)); // Construct result int resultSize = list.size(); if (limit == 0) while (resultSize > 0 && list.get(resultSize - 1).length() == 0) resultSize--; String[] result = new String[resultSize]; return list.subList(0, resultSize).toArray(result); } return Pattern.compile(regex).split(this, limit); }public String[] split(String regex) { return split(regex, 0); }
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