Given a string s and a dictionary of Words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words.
For example, given
s = "leetcode",
dict = ["leet", "code"].
Return true because "leetcode" can be segmented as "leet code".
這道題還是挺有難度的。重點是dynamic PRogramming的應用。用boolean[]來判斷true/false與否。記得除了contians()的條件外還要判斷兩個被分開的單詞是否連在一起這樣的問題。
代碼如下。~
public class Solution { public boolean wordBreak(String s, Set<String> wordDict) { if(s==null&&s.length()==0){ return false; } int len=s.length(); boolean[] test=new boolean[len]; for(int i=0;i<len;i++){ for(int j=0;j<=i;j++){ String sub=s.substring(j,i+1); if(wordDict.contains(sub)&&(j==0||test[j-1])){ test[i]=true; break; } } } return test[len-1]; }}
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