国产探花免费观看_亚洲丰满少妇自慰呻吟_97日韩有码在线_资源在线日韩欧美_一区二区精品毛片,辰东完美世界有声小说,欢乐颂第一季,yy玄幻小说排行榜完本

首頁 > 學(xué)院 > 開發(fā)設(shè)計(jì) > 正文

PAT A1002. A+B for Polynomials (25)

2019-11-14 12:29:26
字體:
供稿:網(wǎng)友

This time, you are supposed to find A+B where A and B are two polynomials.

Input

Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10,0 <= NK < ... < N2 < N1 <=1000.

Output

For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

Sample Input
2 1 2.4 0 3.22 2 1.5 1 0.5Sample Output
3 2 1.5 1 2.9 0 3.2
#include <cstdio>#include <algorithm>#define Max 1234using namespace std;int main(){	double f,c[Max]={};		int n,m,k=0;	scanf("%d",&n);	for(int i=0;i<n;i++)	{		scanf("%d %lf",&m,&f);		c[m]+=f;		}	scanf("%d",&n);	for(int i=0;i<n;i++)	{		scanf("%d %lf",&m,&f);		c[m]+=f;		}	    for(int i=0;i<Max;i++)	{		if(c[i]!=0.0)			k++;	}            PRintf("%d",k);		for(int i=Max-1 ;i>=0;i--)		{			if(c[i]!=0.0)			{				printf(" %d %.1f",i,c[i]);			}		}	system("pause");	return 0;}
發(fā)表評(píng)論 共有條評(píng)論
用戶名: 密碼:
驗(yàn)證碼: 匿名發(fā)表
主站蜘蛛池模板: 孟村| 阿拉善右旗| 旌德县| 靖州| 太谷县| 长治市| 河间市| 赤城县| 绥棱县| 永平县| 鄂托克旗| 图们市| 麻江县| 香河县| 佛坪县| 宣汉县| 南阳市| 西昌市| 嘉定区| 天水市| 建瓯市| 中宁县| 界首市| 科技| 静安区| 逊克县| 淮滨县| 紫金县| 洱源县| 大埔区| 桓台县| 钟祥市| 海口市| 监利县| 盐山县| 旌德县| 茶陵县| 赤水市| 邻水| 枣阳市| 广饶县|