E - Y2K Accounting Bug 題解

2019-11-14 10:23:27

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Accounting for Computer Machinists (ACM) has sufferred from the Y2K bug and lost some vital data for PReparing annual report for MS Inc.All what they remember is that MS Inc. posted a surplus or a deficit each month of 1999 and each month when MS Inc. posted surplus, the amount of surplus was s and each month when MS Inc. posted deficit, the deficit was d. They do not remember which or how many months posted surplus or deficit. MS Inc., unlike other companies, posts their earnings for each consecutive 5 months during a year. ACM knows that each of these 8 postings reported a deficit but they do not know how much. The chief accountant is almost sure that MS Inc. was about to post surplus for the entire year of 1999. Almost but not quite.Write a program, which decides whether MS Inc. suffered a deficit during 1999, or if a surplus for 1999 was possible, what is the maximum amount of surplus that they can post.InputInput is a sequence of lines, each containing two positive integers s and d.OutputFor each line of input, output one line containing either a single integer giving the amount of surplus for the entire year, or output Deficit if it is impossible.Sample Input

59 237375 743200000 8496942500000 8000000Sample Output11628300612Deficit題意：每五個月報一次表，這個表一定是虧得，這五個月為1-5,2-6,3-7.......然后你輸入是s和d，s代表的是每月盈利，d代表每月虧損，問你每年最大能賺多少錢。分6種情況：（x為這五個月中盈利月的個數）1.當x為1時ssssd，ssssd，ss。x為2sssdd，sssdd，ss。x為3ssddd，ssddd，ss。x為4sdddd，sdddd，sd。x為5ddddd，ddddd，dd這時一定虧損，so代碼如下：#include <iostream>using namespace std;int main(){ int s,d; int res; while(cin>>s && cin>>d) {  if(d>4*s)res=10*s-2*d;  else if(2*d>3*s)res=8*s-4*d;  else if(3*d>2*s)res=6*(s-d);  else if(4*d>s)res=3*(s-3*d);  else res=-1;  if(res<0)cout<<"Deficit"<<endl;  else cout<<res<<endl; } return 0;}