国产探花免费观看_亚洲丰满少妇自慰呻吟_97日韩有码在线_资源在线日韩欧美_一区二区精品毛片,辰东完美世界有声小说,欢乐颂第一季,yy玄幻小说排行榜完本

首頁 > 學院 > 開發設計 > 正文

[leetcode]494. Target Sum

2019-11-14 09:49:43
字體:
來源:轉載
供稿:網友

題目鏈接:https://leetcode.com/PRoblems/target-sum/

You are given a list of non-negative integers, a1, a2, ..., an, and a target, S. Now you have 2 symbols + and -. For each integer, you should choose one from + and - as its new symbol.

Find out how many ways to assign symbols to make sum of integers equal to target S.

Example 1:

Input: nums is [1, 1, 1, 1, 1], S is 3. Output: 5Explanation: -1+1+1+1+1 = 3+1-1+1+1+1 = 3+1+1-1+1+1 = 3+1+1+1-1+1 = 3+1+1+1+1-1 = 3There are 5 ways to assign symbols to make the sum of nums be target 3.

Note:

The length of the given array is positive and will not exceed 20.The sum of elements in the given array will not exceed 1000.Your output answer is guaranteed to be fitted in a 32-bit integer.

class Solution{public:    int findTargetSumWays(vector<int>& nums,int S)    {        int count=0;        dfs(nums,count,0,0,S);        return count;    }    void dfs(vector<int>& nums,int &count,int sum,int index,int S)    {        if (index==nums.size())        {            if(sum==S)                count+=1;            return;        }        dfs(nums,count,sum+nums[index],index+1,S);        dfs(nums,count,sum-nums[index],index+1,S);    }};
發表評論 共有條評論
用戶名: 密碼:
驗證碼: 匿名發表
主站蜘蛛池模板: 亚东县| 蓬溪县| 彭山县| 灵宝市| 咸阳市| 玉龙| 泽库县| 定安县| 通州市| 农安县| 习水县| 万山特区| 浮梁县| 微博| 郧西县| 城市| 泰宁县| 洱源县| 冀州市| 洪湖市| 封开县| 禄丰县| 眉山市| 册亨县| 五指山市| 金寨县| 崇阳县| 墨脱县| 泸西县| 永登县| 华阴市| 郴州市| 北海市| 封开县| 抚顺市| 宕昌县| 衢州市| 浪卡子县| 襄城县| 蒙山县| 班戈县|