1. 題目:請(qǐng)編寫一個(gè)c函數(shù),該函數(shù)給出一個(gè)字節(jié)中被置為1的位的個(gè)數(shù)

/*****************************************************copyright (C), 2016-2017, Lighting Studio. Co.,     Ltd. File name：Author：luoye   Version:0.1    Date: Description：Funcion List: *****************************************************/#include <stdio.h>int main(){	int num, mask;	int count=0, i;	PRintf("Please enter a number: ");	scanf("%d",&num);	mask=1<<7;	for(i=0;i<8;i++)	{		if(num&mask)		{			count++;		}		num<<=1;	}	printf("The 1 number is %d/n",count);    return 0;}
2.題目:輸入一個(gè)整數(shù)a,再輸入兩個(gè)整數(shù)p1,p2(p1,p2<32),輸出該整數(shù)的二進(jìn)制表示方法中從右端開始的p1到p2位.
/*****************************************************copyright (C), 2016-2017, Lighting Studio. Co.,     Ltd. File name：Author：luoye   Version:0.1    Date: Description：Funcion List: *****************************************************/#include <stdio.h>int main(){	int num, num1, num2, mask, i;	printf("Please enter a number:");	scanf("%d",&num);	printf("Please enter two number(number<32):");	scanf("%d%d",&num1,&num2);	mask = 1<< num2-1;	for(i = num1; i <= num2; i++)	{		putchar(num&mask ? '1' : '0');		mask >>= 1;	}	printf("/n");    return 0;}
3.題目:輸入一個(gè)整數(shù)a,再輸入兩個(gè)整數(shù)p1,p2(p1,p2<32),將該整數(shù)的二進(jìn)制表示方法中從右端開始的p1到p2位取反后輸出
/*****************************************************copyright (C), 2016-2017, Lighting Studio. Co.,     Ltd. File name：Author：luoye   Version:0.1    Date: Description：Funcion List: *****************************************************/#include <stdio.h>int main(){	int num, num1, num2, mask, i;	printf("Please enter a number:");	scanf("%d",&num);	printf("Please enter two number(number<32):");	scanf("%d%d",&num1,&num2);	mask = 1<< num2-1;	for(i = num1; i <= num2; i++)	{		putchar( num & mask ? '0' : '1');		mask >>= 1;	}	printf("/n");    return 0;}
4. 題目:輸入一個(gè)整數(shù)a,再輸入兩個(gè)整數(shù)p(p<32),v(0|1),將該整數(shù)a的p位設(shè)置為v,輸出修改后的該整數(shù)的二進(jìn)制表示.
/*****************************************************copyright (C), 2016-2017, Lighting Studio. Co.,     Ltd. File name：Author：luoye   Version:0.1    Date: Description：Funcion List: *****************************************************/#include <stdio.h>int main(){	int num, num1, num2, i;	int mask_0, mask_1, mask;	printf("Please enter a number: ");	scanf("%d",&num);	printf("Please enter a number(number<32): ");	scanf("%d",&num1);	printf("Please enter a number(number 0|1): ");	scanf("%d",&num2);	if( num2 == 1)	{		mask_1 = 1<<num1-1;  //生成一個(gè)指定位數(shù)1，其他位數(shù)為0的掩碼		num = num | mask_1;  	}	else	{		mask_0 = 1<<num1-1;  		mask_0 = ~mask_0;     //生成一個(gè)指定位數(shù)為0，其他位數(shù)為1的掩碼		num = num & mask_0;	}	mask =1<<31;	for(i=0;i<32;i++)	{		putchar( num & mask ? '1' : '0');		num <<=1;	}	printf("B/n");    return 0;}
5.題目:輸入一個(gè)32位的整數(shù)a,使用按位異或^運(yùn)算,生成一個(gè)新的32位整數(shù)b,使得該整數(shù)b的每一位等于原整數(shù)a中該位左右兩邊兩個(gè)bit位的異或結(jié)果。
提示:0 ^ 0 = 0; 1 ^ 1 = 0; 0 ^ 1 = 1; 1 ^ 0 = 1;
/*****************************************************copyright (C), 2016-2017, Lighting Studio. Co.,     Ltd. File name：Author：luoye   Version:0.1    Date: Description：Funcion List: *****************************************************/#include <stdio.h>int main(){	int num, num1, mask, mask_p, i;   //num為原來的數(shù)  num1為最后得出的數(shù)	int temp[34];	int sum = 1;	temp[0] = 0;            //默認(rèn)32位的前面后面都為0	temp[33] = 0;	printf("Please enter a number: /n");	scanf("%d",&num);	mask = 1<<31;	for( i = 1; i <= 32; i++)	{		temp[i] = (num & mask ? 1 : 0 );		num <<=1;	}//  輸出原數(shù)的二進(jìn)制表示//	for( i = 0; i < 34; i++)//	{//		printf("%d",temp[i]);//	}//	printf("/n");//相鄰兩位取異或	num1 = 0;	for( i = 32; i >=1; i--)	{		num1 += (temp[i - 1] ^ temp [i+1]) * sum;		sum *= 2 ;             //sum表示二的次方用來得到結(jié)果數(shù)b	}	mask_p = 1<<31;	for( i = 0; i < 32; i++)	{		putchar(num1 & mask_p ? '1' : '0');    //輸出結(jié)果數(shù)的二進(jìn)制表示		num1 <<=1;	}	printf("/n");    return 0;}