国产探花免费观看_亚洲丰满少妇自慰呻吟_97日韩有码在线_资源在线日韩欧美_一区二区精品毛片,辰东完美世界有声小说,欢乐颂第一季,yy玄幻小说排行榜完本

首頁(yè) > 學(xué)院 > 開發(fā)設(shè)計(jì) > 正文

Trapping Rain Water

2019-11-11 06:53:27
字體:
來(lái)源:轉(zhuǎn)載
供稿:網(wǎng)友

Given n non-negative integers rePResenting an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining.

For example, Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6.

The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of rain water (blue section) are being trapped.Thanks Marcos for contributing this image!

int trap(int A[], int n){	int left[n];	int right[n];	int leftMax = 0;	for (int i = 0; i < n; i++)	{		left[i] = leftMax;		leftMax = max(leftMax, A[i]);	}	int rightMax = 0;	for (int i = n-1; i >= 0; i--)	{		right[i] = rightMax;		rightMax = max(rightMax, A[i]);	}	int result = 0;	for (int i = 0; i < n; i++)	{		int temp = min(left[i], right[i]) - A[i];		if (temp > 0)		{			result += temp;		}	}	return result;}


發(fā)表評(píng)論 共有條評(píng)論
用戶名: 密碼:
驗(yàn)證碼: 匿名發(fā)表
主站蜘蛛池模板: 镇沅| 临潭县| 余姚市| 陈巴尔虎旗| 应城市| 含山县| 城固县| 仁化县| 射洪县| 亳州市| 翁牛特旗| 泰和县| 宿松县| 翁牛特旗| 怀化市| 如皋市| 定襄县| 和静县| 凭祥市| 揭西县| 岳阳县| 时尚| 连州市| 伊宁县| 华容县| 息烽县| 托克托县| 屯昌县| 青铜峡市| 宁化县| 肇庆市| 武隆县| 镇远县| 昌吉市| 芮城县| 甘孜| 阿克苏市| 泸水县| 双城市| 三江| 竹山县|