国产探花免费观看_亚洲丰满少妇自慰呻吟_97日韩有码在线_资源在线日韩欧美_一区二区精品毛片,辰东完美世界有声小说,欢乐颂第一季,yy玄幻小说排行榜完本

首頁 > 學院 > 開發設計 > 正文

Common Subsequence [dp]

2019-11-11 02:17:00
字體:
來源:轉載
供稿:網友

A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, …, xm > another sequence Z = < z1, z2, …, zk > is a subsequence of X if there exists a strictly increasing sequence < i1, i2, …, ik > of indices of X such that for all j = 1,2,…,k, x ij = zj. For example, Z = < a, b, f, c > is a subsequence of X = < a, b, c, f, b, c > with index sequence < 1, 2, 4, 6 >. Given two sequences X and Y the PRoblem is to find the length of the maximum-length common subsequence of X and Y.

Input

The program input is from the std input. Each data set in the input contains two strings representing the given sequences. The sequences are separated by any number of white spaces. The input data are correct.

Output

For each set of data the program prints on the standard output the length of the maximum-length common subsequence from the beginning of a separate line. Sample Input abcfbc abfcab programming contest abcd mnp

Sample Output

4 2 0

題解

dp入門題

#include<stdio.h>#include<string.h>#include<algorithm>#define MAX_N 500using namespace std;int dp[2][MAX_N];char a[MAX_N],b[MAX_N];int main(){ while(~scanf("%s%s",a+1,b+1)){ int A=strlen(a+1); int B=strlen(b+1); memset(dp,0,sizeof(dp)); for(int j=1;j<=A;j++) for(int k=1;k<=B;k++){ if(a[j]==b[k]) dp[j&1][k]=dp[(j-1)&1][k-1]+1; else dp[j&1][k]=max(dp[(j-1)&1][k],dp[j&1][k-1]); } printf("%d/n",dp[A&1][B]); } return 0;}
發表評論 共有條評論
用戶名: 密碼:
驗證碼: 匿名發表
主站蜘蛛池模板: 天长市| 凤阳县| 黄冈市| 天全县| 济源市| 杭州市| 海南省| 同仁县| 巍山| 屯昌县| 墨脱县| 内乡县| 犍为县| 如东县| 商丘市| 延津县| 广元市| 甘泉县| 怀安县| 开平市| 汕尾市| 信宜市| 杭州市| 吴桥县| 德格县| 嘉祥县| 西华县| 怀安县| 香港 | 象山县| 乌兰浩特市| 论坛| 南投市| 喜德县| 榆树市| 伊川县| 榆社县| 隆化县| 托里县| 布拖县| 农安县|