Given two arrays, write a function to compute their intersection.
Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2].
Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in any order.
class Solution {public: vector<int> intersect(vector<int>& nums1, vector<int>& nums2) { sort(nums1.begin(), nums1.end()); sort(nums2.begin(), nums2.end()); vector<int> s; for(int i = 0, j = 0; i < nums1.size() && j < nums2.size(); ){ if(nums1[i] < nums2[j]) ++i; else if(nums1[i] > nums2[j]) ++j; else { s.push_back(nums1[i]); ++i; ++j; } } return s; }};新聞熱點(diǎn)
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