1038. Recover the Smallest Number (30)

Given a collection of number segments, you are supposed to recover the smallest number from them. For example, given {32, 321, 3214, 0229, 87}, we can recover many numbers such like 32-321-3214-0229-87 or 0229-32-87-321-3214 with respect to different orders of combinations of these segments, and the smallest number is 0229-321-3214-32-87.

Input Specification:

Each input file contains one test case. Each case gives a positive integer N (<=10000) followed by N number segments. Each segment contains a non-negative integer of no more than 8 digits. All the numbers in a line are separated by a space.

Output Specification:

For each test case, PRint the smallest number in one line. Do not output leading zeros.

5 32 321 3214 0229 87Sample Output:
22932132143287
用string類型保存數(shù)據(jù)，并按照 a + b < b + a排序，拼接后去除前導(dǎo)0，輸出
#include<cstdio>#include<string> #include<algorithm>#include<iostream>/* *字符串排序，去前導(dǎo)0  */using namespace std;const int maxn = 1e5 + 10;string str[maxn];bool cmp(string a, string b){	return a + b < b + a;}int main(){	int n;	cin >> n;	for(int i = 0; i < n; ++i)	{		cin >> str[i];	} 	sort(str, str + n, cmp);	string ans;	for(int i = 0; i < n; ++i)	{		ans += str[i];	}	while(ans.length() > 0 && ans[0] == '0')	{		ans.erase(ans.begin());	}	if(ans.length() == 0)		cout << "0" << endl;	else		cout << ans << endl;	return 0;}