国产探花免费观看_亚洲丰满少妇自慰呻吟_97日韩有码在线_资源在线日韩欧美_一区二区精品毛片,辰东完美世界有声小说,欢乐颂第一季,yy玄幻小说排行榜完本

首頁 > 學(xué)院 > 開發(fā)設(shè)計 > 正文

Longest Ordered Subsequence [dp]

2019-11-11 00:58:46
字體:
供稿:網(wǎng)友

A numeric sequence of ai is ordered if a1 < a2 < … < aN. Let the subsequence of the given numeric sequence ( a1, a2, …, aN) be any sequence ( ai1, ai2, …, aiK), where 1 <= i1 < i2 < … < iK <= N. For example, sequence (1, 7, 3, 5, 9, 4, 8) has ordered subsequences, e. g., (1, 7), (3, 4, 8) and many others. All longest ordered subsequences are of length 4, e. g., (1, 3, 5, 8).

Your PRogram, when given the numeric sequence, must find the length of its longest ordered subsequence.

Input

The first line of input file contains the length of sequence N. The second line contains the elements of sequence - N integers in the range from 0 to 10000 each, separated by spaces. 1 <= N <= 1000

Output

Output file must contain a single integer - the length of the longest ordered subsequence of the given sequence.

Sample Input

7 1 7 3 5 9 4 8

Sample Output

4

題解

#include<stdio.h>#include<string.h>#define MAX_N 1002int a[MAX_N],dp[MAX_N];int main(){ int N; while(~scanf("%d",&N)){ memset(dp,0,sizeof(dp)); int ans=0; for(int i=0;i<N;i++){ scanf("%d",&a[i]); int MAX_cnt=0; for(int j=0;j<i;j++) if(a[i]>a[j]&&MAX_cnt<dp[j]) MAX_cnt=dp[j]; dp[i]=MAX_cnt+1; if(dp[i]>ans) ans=dp[i]; } printf("%d/n",ans); } return 0;}
發(fā)表評論 共有條評論
用戶名: 密碼:
驗證碼: 匿名發(fā)表
主站蜘蛛池模板: 英超| 龙井市| 临城县| 南汇区| 韶关市| 黄梅县| 罗城| 兴文县| 平果县| 平谷区| 巴东县| 合山市| 正安县| 南华县| 松桃| 蒙自县| 澳门| 醴陵市| 吴忠市| 雷山县| 霍邱县| 通渭县| 新宁县| 怀远县| 泽普县| 姜堰市| 汕头市| 平罗县| 东港市| 安溪县| 绥阳县| 四会市| 遂溪县| 枣庄市| 桐柏县| 浑源县| 泗阳县| 漳浦县| 东源县| 和顺县| 黎城县|