国产探花免费观看_亚洲丰满少妇自慰呻吟_97日韩有码在线_资源在线日韩欧美_一区二区精品毛片,辰东完美世界有声小说,欢乐颂第一季,yy玄幻小说排行榜完本

首頁 > 學(xué)院 > 開發(fā)設(shè)計(jì) > 正文

Longest Ordered Subsequence [dp]

2019-11-11 00:22:16
字體:
供稿:網(wǎng)友

A numeric sequence of ai is ordered if a1 < a2 < … < aN. Let the subsequence of the given numeric sequence ( a1, a2, …, aN) be any sequence ( ai1, ai2, …, aiK), where 1 <= i1 < i2 < … < iK <= N. For example, sequence (1, 7, 3, 5, 9, 4, 8) has ordered subsequences, e. g., (1, 7), (3, 4, 8) and many others. All longest ordered subsequences are of length 4, e. g., (1, 3, 5, 8).

Your PRogram, when given the numeric sequence, must find the length of its longest ordered subsequence.

Input

The first line of input file contains the length of sequence N. The second line contains the elements of sequence - N integers in the range from 0 to 10000 each, separated by spaces. 1 <= N <= 1000

Output

Output file must contain a single integer - the length of the longest ordered subsequence of the given sequence.

Sample Input

7 1 7 3 5 9 4 8

Sample Output

4

題解

#include<stdio.h>#include<string.h>#define MAX_N 1002int a[MAX_N],dp[MAX_N];int main(){ int N; while(~scanf("%d",&N)){ memset(dp,0,sizeof(dp)); int ans=0; for(int i=0;i<N;i++){ scanf("%d",&a[i]); int MAX_cnt=0; for(int j=0;j<i;j++) if(a[i]>a[j]&&MAX_cnt<dp[j]) MAX_cnt=dp[j]; dp[i]=MAX_cnt+1; if(dp[i]>ans) ans=dp[i]; } printf("%d/n",ans); } return 0;}
發(fā)表評論 共有條評論
用戶名: 密碼:
驗(yàn)證碼: 匿名發(fā)表
主站蜘蛛池模板: 金昌市| 温宿县| 克山县| 仁寿县| 乌兰浩特市| 中阳县| 新邵县| 察雅县| 读书| 佛山市| 沛县| 铅山县| 雅江县| 伊春市| 凤城市| 澄迈县| 长子县| 北碚区| 桃江县| 巴楚县| 泰兴市| 墨江| 蒙山县| 嘉善县| 东乡县| 海丰县| 嘉义县| 都安| 峨山| 揭东县| 桐庐县| 山阴县| 调兵山市| 西吉县| 防城港市| 托克逊县| 张北县| 准格尔旗| 浮梁县| 新邵县| 齐齐哈尔市|