Groovy集合Map

person = ["Mike": "ShangHai", "Lily" : "BeiJing", "Jack" : "ShangHai"]PRintln person.getClass().name // java.util.LinkedHashMap2、[]和.操作符獲取Map中的元素。
println person["Mike"] // ShangHaiprintln person.Lily // BeiJingprintln person['Lili'] // null3、each方法實現迭代，既可以使用一個參數entry，也可以使用兩個參數name，city。
person.each {entry ->	println "$entry.key live in $entry.value"}
person.each {name, city ->	println "$name live in $city"}返回Mike live in ShangHaiLily live in BeiJingJack live in ShangHai4、collect方法返回一個集合。
println person.collect { name, city -> name } // [Mike, Lily, Jack]5、查找方法find和findAll，find返回第一個，findAll返回全部。
person = ["Mike": "ShangHai", "Lily" : "BeiJing", "Jack" : "ShangHai"]selected = person.find {name, city ->    city == "ShangHai"}println selected // Mike=ShangHaiselected = person.findAll {name, city ->    city == "ShangHai"}println selected // [Mike:ShangHai, Jack:ShangHai]6、groupBy分組。
groups = person.groupBy { it.value} println groups // [ShangHai:[Mike:ShangHai, Jack:ShangHai], BeiJing:[Lily:BeiJing]]groups.each{ city, persons ->	println city	for (p in persons) {		println "$p.key live in $p.value"	}}返回
[ShangHai:[Mike:ShangHai, Jack:ShangHai], BeiJing:[Lily:BeiJing]]ShangHaiMike live in ShangHaiJack live in ShangHaiBeiJingLily live in BeiJing