題目是： N個人圍成一圈報數，報到某一個數m的就出局，問你最后剩下來的人的號碼？
網上通用約瑟夫環的算法是：
//函數接收n和m，返回最后出圈的是第幾個人 /*e.g. yuesefu(5,2)=3 yuesefu(2,100)=1*/ int yuesefu(int n,int m) { int i,r=0; for (i=2;i <=n;i++) r=(r+m)%i; return r+1; }用python實現上面算法為：
def yuesefu2(n, m): # 網上常見方法，答案準確 # yuesefu2(50, 5)=19 i = 0 r = 0 for i in range(2, n + 1): r = (r + m) % i return r + 1用python模擬報數出局的方法為：
def yuesefu3(n, m): a = range(1, n + 1) b = [] i = 0 # 指針 while n > 1: i = i + m if i > n: i = i % n b.append(a.pop(i - 1)) # PRint a.pop(i-1) n = n - 1 i = i - 1 if i == n or i == -1: # 特別處理，如果正好彈出最后一個，i值歸0 i = 0 b.append(a[0]) return bif __name__ == '__main__': n = 60 m = 99 print u'約瑟環2:' + str(yuesefu2(n, m)) print u'約瑟環3:' + str(yuesefu3(n, m))50人報5出局答案，及出局順序為： 約瑟環2:19 約瑟環3:[5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 6, 12, 18, 24, 31, 37, 43, 49, 7, 14, 22, 29, 38, 46, 3, 13, 23, 33, 42, 2, 16, 27, 39, 1, 17, 32, 47, 11, 34, 4, 26, 48, 28, 9, 44, 41, 8, 21, 36, 19]
30人報3出局答案，及出局順序為： 約瑟環2:29 約瑟環3:[3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 4, 8, 13, 17, 22, 26, 1, 7, 14, 20, 28, 5, 16, 25, 10, 23, 11, 2, 19, 29]
60人報99出局答案，及出局順序為： 約瑟環2:55 約瑟環3:[39, 19, 1, 45, 30, 17, 7, 58, 52, 48, 46, 47, 51, 57, 6, 16, 29, 44, 10, 32, 2, 31, 9, 43, 28, 21, 14, 13, 20, 27, 42, 8, 38, 22, 4, 60, 11, 26, 54, 36, 34, 41, 12, 56, 5, 40, 49, 23, 33, 25, 18, 15, 37, 50, 59, 53, 24, 3, 35, 55]
新聞熱點
疑難解答
